Earlier quoted context omitted.
Let me try to do it without Avogadro's number approximately: m_oxygen / m_carbon = (n_oxygen * A_oxygen) / (n_carbon * A_carbon) m_oxygen = x * (2 * 16) / (1 * 12) = 2.7 x and more accurately: m_oxygen / m_carbon = n_oxygen * m_oxygen / n_carbon * m_carbon m_oxygen = x * (2 * 26.567 yg) / (1 * 19.945 yg) = 2.664 x Can you do it more easily using Avogadro's number?
Where did you get the A_oxygen and A_carbon in first part? Take the same calculation, use 12,01 for carbon and 16,00 for oxygen. Values in one reference book, get 2,66444629475 or the 2,644. Avogadro's number is just number of atoms in the mole. Making atomic masses sensible numbers. Carbon dioxide is actually relatively bad example as both values are close to integers. Chloride with atomic mass 35,45 starts to be mo…
If you have to look up a 4-digit number, it's not easier to look up or use 12.01 u instead of 19.95 yg, especially with higher atomic masses where they're less integer-like, as you say. But using u involves more conceptual complexity because you're mixing two different mass units (u and g) in the same calculation. That's the part that's hard to do in your head. Chemistry students often struggle with this whole concept, which comes with a whole parallel collection of formulas and quantities to work with the alternative mass unit. They more easily understand SI prefixes which is just reusing an existing well-known concept.
You don't need to struggle with doin math on very tiny numbers any more than electrical engineers have to struggle with picofarads and nanoseconds.