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Jewish Problems (2011) [pdf]

arxiv.org

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Re: Jewish Problems (2011) [pdf]

#21

Post by naniwaduni »

mjfl wrote: post #6
samdung wrote: post #5

How many digits does the number 125^100 have? Im breaking my head here :(

100*log10(125) ~ 210?

We've reduced a tedious elementary problem to a slightly harder problem!

(We can observe that 125 = 1000/8, so 100log10(125) = 300 - 300log10(2) = 300 - 30log(1024). From here we merely need the bound 90 = 30log(1000) < 30log(1024) < 91, or equivalently 1 < 1.024^30 < 10. There are probably better approaches but I'm partial to 1.024^30 = (1.024^15)^2 < (1.024^16)^2 < 3^2 < 10, since 1.024^16 is easy to upper bound by repeated squaring and rounding up: 1.024^16 < 1.03^16 < 1.1^8 < 1.3^4 < 1.7^2 < 2.9.)

Re: Jewish Problems (2011) [pdf]

#23

Post by sek »

kingkawn wrote: post #13
kingbirdy wrote: post #11

Earlier quoted context omitted.

I don't mean to attack your recent revelation, but my understanding was that Judaism is matrilineal, so if your mother isn't Jewish and you don't practice then you're not Jewish (unless this has made you want to convert). It's also certainly possible I don't fully understand the situation or the custom.

That is true among the orthodox and some hardline conservatives, not reform or reconstructionists

Only reform Jews in America and they require jewish upbringing. I would recommend sillysaurusx going trough the conversion process at your reform Synagogue. (Reform is mostly about knowledge, basically classes). It’s there for a reason, you learn a lot if you didn‘t have an upbringing.

My situation was similar, matrilineal but my mum is baptized. I wasn’t required to, but I am glad to understand now what rabbinical judaism actually is.

Re: Jewish Problems (2011) [pdf]

#24

Post by rumanator »

ggm wrote: post #3

This is also how the "white australia" policy was manipulated to exclude "undesirables" -A famous instance was the use of gaelic as a language test on somebody: and what do you know, it was a Jewish political activist! https://en.wikipedia.org/wiki/Attempted_exclusion_of_Egon_Ki...

A representative of the Communist International trying to infiltrate a country under false pretexted through a front organization is hardly a mere "Jewish political activist". It's quite the stretch, and quite the spin, to try to portray Egon Kisch's adventure as something related to jewishness.

Re: Jewish Problems (2011) [pdf]

#25

Post by mdturnerphys »

sillysaurusx wrote: post #7

The reason I submitted this was, incidentally, that I discovered I am Jewish. My father was the first to marry outside of the faith, so it’s apparently a long lineage. I’m not sure how to feel. Reactions range from “So what?” to “I have a culture?” I’ve been at least trying to study some history. It’s still kind of amazing it never came up once. It was almost accidental that I found out at all. (Random census questio…

Thanks for sharing. Best wishes in exploring your newfound heritage.

Re: Jewish Problems (2011) [pdf]

#26

Post by onyva »

And today we have so called Jews (meaningless descriptor from an ethnic point of view in respect to Eastern Europeans) advising Trump how to make life hell for other minorities. Ie Miller and Kushner and the rest of trump’s Eastern European “advisers”. https://www.nature.com/articles/ncomms3543

Re: Jewish Problems (2011) [pdf]

#27

Post by mjfl »

naniwaduni wrote: post #21
mjfl wrote: post #6

Earlier quoted context omitted.

100*log10(125) ~ 210?

We've reduced a tedious elementary problem to a slightly harder problem! (We can observe that 125 = 1000/8, so 100log10(125) = 300 - 300log10(2) = 300 - 30log(1024). From here we merely need the bound 90 = 30log(1000) < 30log(1024) < 91, or equivalently 1 < 1.024^30 < 10. There are probably better approaches but I'm partial to 1.024^30 = (1.024^15)^2 < (1.024^16)^2 < 3^2 < 10, since 1.024^16 is easy to upper bound by…

observe that log10(125) = log10(100) + log10(1.25)

log10(100) = 2

log10(1.25) = log(1 + 0.25) / log(10) ~ 0.25 / log(10) Thus log10(125) ~ 2.12 but probably a little less.

Re: Jewish Problems (2011) [pdf]

#28

Post by 29athrowaway »

kingbirdy wrote: post #20
29athrowaway wrote: post #16

How many correct answer did you need to pass? What was the passing rate?

According to the paper, they would just keep asking questions until you failed, there was no passing if they didn't want you to enroll.

Something similar, but not as severe, existed in the US.

https://en.wikipedia.org/wiki/Jewish_quota#United_States

One of the people excluded due to that system was Richard Feynman.

Re: Jewish Problems (2011) [pdf]

#29

Post by ggm »

rumanator wrote: post #24
ggm wrote: post #3

This is also how the "white australia" policy was manipulated to exclude "undesirables" -A famous instance was the use of gaelic as a language test on somebody: and what do you know, it was a Jewish political activist! https://en.wikipedia.org/wiki/Attempted_exclusion_of_Egon_Ki...

A representative of the Communist International trying to infiltrate a country under false pretexted through a front organization is hardly a mere "Jewish political activist". It's quite the stretch, and quite the spin, to try to portray Egon Kisch's adventure as something related to jewishness.

The substantive point was the use of a language test, subject to manipulation of what was the Anglo Celtic language.

Re: Jewish Problems (2011) [pdf]

#30

Post by naniwaduni »

mjfl wrote: post #27
naniwaduni wrote: post #21

Earlier quoted context omitted.

We've reduced a tedious elementary problem to a slightly harder problem! (We can observe that 125 = 1000/8, so 100log10(125) = 300 - 300log10(2) = 300 - 30log(1024). From here we merely need the bound 90 = 30log(1000) < 30log(1024) < 91, or equivalently 1 < 1.024^30 < 10. There are probably better approaches but I'm partial to 1.024^30 = (1.024^15)^2 < (1.024^16)^2 < 3^2 < 10, since 1.024^16 is easy to upper bound by…

observe that log10(125) = log10(100) + log10(1.25) log10(100) = 2 log10(1.25) = log(1 + 0.25) / log(10) ~ 0.25 / log(10) Thus log10(125) ~ 2.12 but probably a little less.

The extra contortions are to get a bound tight enough to admit only one integer.
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