Earlier quoted context omitted.
A lot less. $ 1,283,305,580,313,390
I think that's the payment on day 365, not the year total. Edit: It is. I just ran the code again, and the payment for day 365 is 1.28331e+15
You are right. I was wrong.
I wear your shirt
31–34 of 34 posts
Re: I wear your shirt
#32Earlier quoted context omitted.
We can't all be Gauss but, then again, we're not in fourth grade anymore, either. You can sum over any range trivially: average of the endpoints times length of the range. The average of 1 and 365 is 183. There are 365 elements between 1 and 365 (both inclusive). 183 * 365 = 66795. Yay, right answer. (There is a formula. I have a poor memory for formulas but am good at transforming English into them, so I just rememb…
I was referring to the fact that Wolfram actually understood the input, not that it answered a trivial math question :)
(loop for x from 1 to 365 summing x) ==> 66795Re: I wear your shirt
#33Earlier quoted context omitted.
Python: reduce (operator.add, range(366))
or sum(range(366))
(sum (range 1 365))
(defun range (start end)
(loop for x from start to end collecting x))
(defun sum (sequence)
(reduce #'+ sequence))Re: I wear your shirt
#34Earlier quoted context omitted.
didn't even think of that one! :)
or plain math: n(n+1)/2
How quickly can you generalize the plain math formula to these sequences: http://www.research.att.com/njas/sequences/index.html