> Under OpenBSD, that values would not have been uninitialized, were it not for OpenSSL's silly malloc wrapper -- a contraption of the sort that, if they really wanted, they could probably implement on top of Rust as well. What is arguably a logic mistake compromised the protection of a runtime that, just like Rust, claimed that it would not allow uninitialized values, "by design".
I really disagree. Rust does not allow uninitialized values by design - end of story. If a piece of Rust code let's uninitialized values bleed through, then it is broken. The semantics of Rust demands this.
(OpenSSL on the other hand only broke/Overrode OpenBSD's malloc - they didn't break C.)
It is news to no one that you can break - break - Rust's semantics if you use anything that demands `unsafe`. That's why anyone who uses `unsafe` and intends to wrap that `unsafe` in a safe interface has to be very careful.
Complaining about Rust being unsafe - in the specific sense that the Rust devs use - by using the `unsafe` construct, is like complaining that Haskell is impure because you can use `unsafePerformIO` to `launchMissiles` from a non-IO context.
> Of course, idiomatic Rust code would not fall into that trap -- but then arguably neither would idiomatic C code.
It's not even a question of being idiomatic. If someone codes in safe (non-`unsafe`) Rust, then they should not fall into the trap that you describe. If they do, then someone who implemented something in an `unsafe` block messed up and broke Rust's semantics.
What if that same thing happened in C? Well, then it's just another bug.
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I'd bet you'd be willing to take it to its next step, even if we assume that a language is 100% safe from X no matter what the programmer does - "what if the compiler implementation is broken?". And down the rabbit hole we go.