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Raytracing a Black Hole

rantonels.github.io

31–40 of 40 posts

Re: Raytracing a Black Hole

#31
Nice introduction. My colleague works exclusively in raytracing around black holes (although he uses the Kerr metric) and he has produced some really cool images.

I highly recommend looking at the literature for really cool images with more complicated black holes.

Re: Raytracing a Black Hole

#32

Would be great if they coded this into Elite: Dangerous.

Now that Interstellar brought this image of a black hole into popular culture, I expect many other movies and games adopting it.

Interstellar? How about 'black hole'? http://www.imdb.com/title/tt0078869/

Re: Raytracing a Black Hole

#33

Earlier quoted context omitted.

Now that Interstellar brought this image of a black hole into popular culture, I expect many other movies and games adopting it.

Interstellar? How about 'black hole'? http://www.imdb.com/title/tt0078869/

I haven't watched that movie, but I did look at screenshots, and what I see is the bog standard black hole used by everyone everywhere. And I'm not really surprised - after all, Interstellar invented the black hole image this article was talking about, AFAIR it was for this movie that such rendering was attempted the first time ever - so for your reference to be relevant to my comment, we'd have to be dealing with some really serious time travel stuff. ;).

Re: Raytracing a Black Hole

#34
post #20

Performance thought: I like the way you raytrace the entire image at once. Clever, but you might be able to make it faster... Right now you process the entire image in one hit. However a 1080p * 4 byte image is 777,600 bytes - from a quick read I believe you have several of these. They're large enough to blow the caches in your CPU. It might be much faster to break the image into 8,16 or 32 square or rectangular or l…

I don't get something. Isn't 1080p a 1920x1080 image, which would make it 2073600px * 4 bytes = 8294400 bytes = 7.91 megabytes?

Re: Raytracing a Black Hole

#36
post #21

Earlier quoted context omitted.

Is it fair to compare this low-res photo to the render? I think they'll be prettier once we have better telescopes.

it's not about fairness, that's what we see currently.

What if "what we see" is not accurate of how it actually looks and works? I think the math behind it would have a more accurate way to describe how it looks and works, which is what the render does.

Re: Raytracing a Black Hole

#38
post #25

Earlier quoted context omitted.

Wow, I hadn't thought of that. I wonder what the "compression" factor is for each orbit around the black hole. Edit: Actually, I don't think you get any photons that do a full 360 degrees around the black hole that subsequently escape the black hole.

If you look at the image of geodesics he shows an example of an almost 360 degree trajectory. Simple continuity arguments allow you to conclude you can have an arbitrary number of rotations, I believe. I would conjecture the contraction is roughly exponential, there's no obvious contradiction with that but it's way over by knowledge to check it ...

By the time a photon has done a complete rotation, it necessarily has to be on a path that takes it into the black hole (instead of outside of it). So yes, you can have an arbitrary number of rotations, but anything that makes a complete rotation or more will never leave the black hole.

Re: Raytracing a Black Hole

#39
post #38

Earlier quoted context omitted.

If you look at the image of geodesics he shows an example of an almost 360 degree trajectory. Simple continuity arguments allow you to conclude you can have an arbitrary number of rotations, I believe. I would conjecture the contraction is roughly exponential, there's no obvious contradiction with that but it's way over by knowledge to check it ...

By the time a photon has done a complete rotation, it necessarily has to be on a path that takes it into the black hole (instead of outside of it). So yes, you can have an arbitrary number of rotations, but anything that makes a complete rotation or more will never leave the black hole.

Hmm I'm not so sure anymore. I'll have to ask a physicist I guess.

Re: Raytracing a Black Hole

#40
post #38

Earlier quoted context omitted.

If you look at the image of geodesics he shows an example of an almost 360 degree trajectory. Simple continuity arguments allow you to conclude you can have an arbitrary number of rotations, I believe. I would conjecture the contraction is roughly exponential, there's no obvious contradiction with that but it's way over by knowledge to check it ...

By the time a photon has done a complete rotation, it necessarily has to be on a path that takes it into the black hole (instead of outside of it). So yes, you can have an arbitrary number of rotations, but anything that makes a complete rotation or more will never leave the black hole.

It turns out that a photon can describe any real rotation angle around a black hole (I've asked a physicist). The continuity argument I gave is valid: take the critical energy E wherein the photon is attached to the photosphere, then with an adequate E+eps, eps > 0, the photon will describe an according monotonically decreasing angle.
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