Earlier quoted context omitted.
You could use Function.prototype.bind in a couple ways, or even Array.prototype.map (though sadly you can't really do new Array(n).map, if that was true you could make this a one-liner). // new Array(n) could just be [] in all examples // // using Array.prototype.map // sadly you can't do new Array(n).map // because it doesn't iterate over undefined functions function foo(n) { for (var ret = new Array(n), i = 0; i
If you're into one-liners, CoffeeScript is your friend :) foo = (n) -> (-> i) for i in [0..n]
Close, but I checked it and the value of `i` won't bind to the function. You also have to use `...` (exclusive range) instead of `..` to prevent an off-by-one error.
Here's one way:
foo = (n) -> ((a) -> a).bind(null, i) for i in [0...n]
foo = (n) -> (-> +@).bind i for i in [0...n]