jSpy: Automatically detect user's history

If you want to check the source code write in your console:

    var updateParams2 = updateParams;
    function (){debugger; updateParams2()};

then click the button and step in. Here is a part of the source, hope the author doesn't mind about this:

    urls = [
    function initStats() {
        currentUrl = 0;
        start = NaN;
        counter = 0;
        posTimes = [];
        negTimes = [];
        if (stop) {
            stop = false;
            loop()
        }
    }
    function updateParams() {
        out.style.textShadow = "black 1px 1px 60px";
        out.style.opacity = "0.5";
        out.style.fontSize = "15px";
        textLines = (window.textlines ? window.textlines : 100);
        textLen = (window.textlen ? window.textlen : 5);
        write();
        resetLinks();
        initStats()
    }
    function write() {
        var c = "";
        var a = urls[currentUrl];
        var d = "";
        while (d.length " + d;
            c += " "
        }
        out.innerHTML = c
    }
    function updateLinks() {
        var a = urls[currentUrl];
        for (var b = 0; b  4) {
                    if (currentUrl == 0) {
                        document.getElementById("nums").textContent = "Calibrating...";
                        posTimes.push(d);
                        timespans[currentUrl].textContent = posTimes.join(", ")
                    }
                    if (currentUrl == 1) {
                        negTimes.push(d);
                        timespans[currentUrl].textContent = negTimes.join(", ");
                        if (negTimes.length >= calibIters) {
                            var b = median(posTimes);
                            var a = median(negTimes);
                            if (b - a = 2) {
                        timespans[currentUrl].textContent = d;
                        linkspans[currentUrl].className = (d >= threshold) ? "visited yes" : "visited";
                        if ((d >= threshold) == true) {
                            window.links.push(urls[currentUrl])
                        }
                        incUrl = true
                    }
                    currentUrl++;
                    if (currentUrl == 2 && (negTimes.length Time elapsed: " + timeElapsed + "s, tested " + (((urls.length - 2) / timeElapsed) | 0) + " URLs/sec";
                        stop = true;
                        finishjSpy()
                    }
                    if (currentUrl > 2) {
                        $(".analyze_log").html(urls[currentUrl])
                    } else {
                        $(".analyze_log").html("Calibrating... ")
                    }
                    currentURLout.textContent = urls[currentUrl]
                }
            } else {
                updateLinks()
            }
        }
        requestAnimationFrame(loop)
    }
    function setupLinks() {
        window.links = [];
        var f = document.createElement("table");
        f.innerHTML = "URLTimes (ms)";
        f.className = "linklist";
        for (var e = 0; e " + b + "")
        });
        $(".content").fadeOut();
        $(".jspy").remove();
        setTimeout(function() {
            $(".content").remove();
            $(".results").fadeIn()
        }, 500)
    }
    ;

Thanks for the suggestions, I implemented them, and also un-obfuscated and formatted the code. Also, now it's much faster since it doesn't use DOM.

No, I ran the code through an optimizer and checked "remove last semicolon".

I run it in the Tint browser on Android and got Hacker News plus a few false positives, sites I never heard about and never been at (maybe some images included in other sites?). I got a much longer list of sites in Dolphin but that's my main Android browser. Again, many unknown sites but I can't remember or notice any random link I touch. I tried again with Chromium on Linux and got the cannot calibrate message. Firefox is my main browser and is not supported, luckily, let me add :-)

This really didn't work at all. I'm using the latest stable Chrome on a Mac. Roughly 3/4 of the results (there's too many to bother counting) are sites I've never been to.