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Show HN: Logarithmic Flappy 2048

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Re: Show HN: Logarithmic Flappy 2048

#31

I would describe this as multiplicative rather than logarithmic. 2×2×2×2... Or maybe exponential if you consider your score to be 2^(number of walls you've jumped). I don't get logarithmic, though.

This is the exponential function, 2^x. Where the independent variable is the number of walls jumped. For instance, after 30 jumps, your score/tile reads 1073741824, or 2^30.

Re: Show HN: Logarithmic Flappy 2048

#32

I would describe this as multiplicative rather than logarithmic. 2×2×2×2... Or maybe exponential if you consider your score to be 2^(number of walls you've jumped). I don't get logarithmic, though.

This is the exponential function, 2^x. Where the independent variable is the number of walls jumped. For instance, after 30 jumps, your score/tile reads 1073741824, or 2^30.

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Re: Show HN: Logarithmic Flappy 2048

#34

I would describe this as multiplicative rather than logarithmic. 2×2×2×2... Or maybe exponential if you consider your score to be 2^(number of walls you've jumped). I don't get logarithmic, though.

This is the exponential function, 2^x. Where the independent variable is the number of walls jumped. For instance, after 30 jumps, your score/tile reads 1073741824, or 2^30.

Or it's the logarithmic function lg(x), where the independent variable is the score and the dependent variable is roughly proportional to the number of times you've clicked.

Re: Show HN: Logarithmic Flappy 2048

#36
Quite a coincidence that I see this tonight. I was on the bus today and noticed someone playing a game on their phone, something simple where you have to trace over a pattern as closely as you can. It was frustrating to watch because every time the user wanted to repeat a level or move on to the next, they were forced to tap through a couple of intermediary screens with flashy stats that took up as much time to get through as playing a level. Contrast that to this game where starting over takes me 0.0 seconds. You jump right back into gameplay, forgetting all the frustration that came with messing up on your previous attempt. More games should take note.

Re: Show HN: Logarithmic Flappy 2048

#38

Earlier quoted context omitted.

This is the exponential function, 2^x. Where the independent variable is the number of walls jumped. For instance, after 30 jumps, your score/tile reads 1073741824, or 2^30.

Or it's the logarithmic function lg(x), where the independent variable is the score and the dependent variable is roughly proportional to the number of times you've clicked.

Well yes, logbase2(x), where x is your score, does equal the number of wall jumps. But that doesn't account for how the game is laid out. Your score is a result of the number of jumps you've made. The number of jumps you've made is not the result of your score. Therefore, despite these two functions being the inversely related, the correct relationship is 2^x. That is just my opinion though.

Re: Show HN: Logarithmic Flappy 2048

#39

Earlier quoted context omitted.

Or it's the logarithmic function lg(x), where the independent variable is the score and the dependent variable is roughly proportional to the number of times you've clicked.

Well yes, logbase2(x), where x is your score, does equal the number of wall jumps. But that doesn't account for how the game is laid out. Your score is a result of the number of jumps you've made. The number of jumps you've made is not the result of your score. Therefore, despite these two functions being the inversely related, the correct relationship is 2^x. That is just my opinion though.

I agree "exponential" would have been a more natural choice.

"Therefore, despite these two functions being the inversely related, the correct relationship is 2^x."

There is no "correct relationship", there is a relationship that (depending on choice of variables) we can describe as y=2^x or y=lg(x).

Re: Show HN: Logarithmic Flappy 2048

#40

Earlier quoted context omitted.

Well yes, logbase2(x), where x is your score, does equal the number of wall jumps. But that doesn't account for how the game is laid out. Your score is a result of the number of jumps you've made. The number of jumps you've made is not the result of your score. Therefore, despite these two functions being the inversely related, the correct relationship is 2^x. That is just my opinion though.

I agree "exponential" would have been a more natural choice. "Therefore, despite these two functions being the inversely related, the correct relationship is 2^x." There is no "correct relationship", there is a relationship that (depending on choice of variables) we can describe as y=2^x or y=lg(x).

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