Earlier quoted context omitted.
> The pattern will break down It doesn't actually: 4096 8193 6387 = 4096+8192 + 1 6384 + …
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1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
41–50 of 109 posts
Re: 1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
#42I gotta be that guy: Why is this the first post on the front page of Hacker News? Is basic arithmetic really so fascinating to the computer people?
Re: 1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
#43Re: 1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
#44The pattern will break down once you get past 8192, which is 2^13. That means that the pattern continues for an impressive 52 significant figures (well, it actually breaks down on the 52nd digit, which will be a 3 instead of a 2). The reason it works is that 9998 = 10^4 - 2. You can expand as 1 / (10^n - 2) = 1/10^n * 1/(1 - 2/10^n) = 1/10^n * (1 + 2/10^n + 2^2 /10^2n + 2^3 /10^3n + ...) which gives the observed patt…
> The pattern will break down It doesn't actually: 4096 8193 6387 = 4096+8192 + 1 6384 + …
Re: 1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
#45Re: 1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
#46In high school, I was pretty fond of plugging 11^n to get rows of Pascal's triangle. It breaks down at row 5, but inserting 0's in the middle extends it (e.g. 101^n, 1001^n, 10001^n). 11^0 1 11^1 1 1 11^2 1 2 1 11^3 1 3 3 1 11^4 1 4 6 4 1
5th row: 1 5 10 10 5 1
Writing this a bit backwards, 1 * 1 + 5 * 10 + 10 * 100 + 10 * 1000 + 5 * 10000 + 1 * 100000 = 161051 = 11^5.
Re: 1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
#47I gotta be that guy: Why is this the first post on the front page of Hacker News? Is basic arithmetic really so fascinating to the computer people?
Re: 1/9998 = 0.0001 0002 0004 0008 0016 0032 0064 0128 0256..
#48I gotta be that guy: Why is this the first post on the front page of Hacker News? Is basic arithmetic really so fascinating to the computer people?