11–20 of 84 posts
How huge is a 1mm beam when it hits the moon (and visa-versa) ? I wonder if wolframalpha can tell me... Actually, I don't even know how to ask it the proper question. Can anyone make this formula work in wolfram? http://laserpointerforums.com/attachments/f51/17952-calculat... update: I think I figured this out as ((λ * L) / d)* 2 (((630nm in meters)*(380000km in meters)) / (1mm in meters)) * 2 Which would be a nearly…
Either way, it's pretty incredible. Even if the 622 Mbps down isn't completely error free, but maybe 99%, you just need to use a video compression algorithm that is error tolerant.
The latency must be huge though.
Or would it? Perhaps simply increasing the retransmission timer would give us interplanetary internet. I wonder.
The latency must be huge though.
I'd imagine TCP, as a protocol starts to fall over with moon-to-earth latencies. Or would it? Perhaps simply increasing the retransmission timer would give us interplanetary internet. I wonder.
The latency must be huge though.
I'd imagine TCP, as a protocol starts to fall over with moon-to-earth latencies. Or would it? Perhaps simply increasing the retransmission timer would give us interplanetary internet. I wonder.
The article cites 622 Mbps down, 20 Mbps error-free up. Is the implication that the 622 Mbps down is before error correction? Either way, it's pretty incredible. Even if the 622 Mbps down isn't completely error free, but maybe 99%, you just need to use a video compression algorithm that is error tolerant.
Earlier quoted context omitted.
I'd imagine TCP, as a protocol starts to fall over with moon-to-earth latencies. Or would it? Perhaps simply increasing the retransmission timer would give us interplanetary internet. I wonder.
Moon to earth should be workable enough...average speed of light roundtrip will be about 2400ms.