Earlier quoted context omitted.
That is accurate. The object reference by immutable msg is hello_world which is mutable. If the value of hello_world changes, then the value of msg changes too. In the simple example, it won't happen, but the point is that it could , especially when multi-threaded.
I don't buy it, by calling that function, the caller is saying the value won't change underneath you (because you are being called in multithreaded code). The object itself cannot change itself, though of course there can be mutable members, which tend to be syncronisation mechanisms (mutexes) anyway.
You really do not understand what "const" means in C++.
If what you said were true, a whole class of optimizations would be possible that are not currently possible. For example, consider this silly function:
void f(const int *x) {
int y = *x;
g();
if (y == *x) h();
}
If what you said were true, this would be able to optimize away the call to h() completely, but if you compile the function with maximum optimization you will see that this is not the case. Why not? Because the caller could look like this: int val = 0;
void g() { val = 1; }
int main() { f(&val); }