This is in the zip documentation as the way of solving this problem. Sort of surprised the author didn't look up the documentation before writing what is otherwise a very good post. The left-to-right evaluation order of the iterables is guaranteed. This makes possible an idiom for clustering a data series into n-length groups using zip(*[iter(s)]*n). http://docs.python.org/2/library/functions.html#zip
This is one of those cases where Ruby does it better (s.each_slice(3).to_a).