Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
1–10 of 40 posts
Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#2Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#3(0.5 * 2X) + (0.5 * 0) = X = (X * 1.0)
but perhaps you would be able to attract more customers. I doubt it. While it's certainly true that everybody loves a freebie, no one likes to pay twice for something.
Why not charge X with probability (1-p) and charge zero with probability p? The expected value would be reduced to (1-p) but perhaps you would attract people looking for freebies. More customers is always a good thing, right?
Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#4Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#5On a practical note, what stops them getting a refund and repurchasing until they get it for free.
Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#6There's always going to be less people you can afford 2X than X.
Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#7Car dealerships seem to like this one, and Visa ran a similar contest here in Canada recently (called "Win What You Buy").
The success of this kind of promotion is most likely proportional to the price of your product.
Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#8Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#9There's a reason why people indulge "If I won the lottery..." fantasies.
Re: Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
#10If you make people commit before revealing the amount, the issue is trust: how do customers know that the odds are actually 1/2 that they'll pay $0? How do they know you aren't just charging everyone $2X? You'd have to use some verifiably random bit, which gets complicated. People will smell a scam.
(Speaking of which: are there any commonly used publicly verifiable random numbers, like a die roll, but outside of any party's control? I presume there must be a need for them in a number of situations.)