Earlier quoted context omitted.
There are some interesting reasons for that. When a lot of transistors in an integrated circuit all switch at the same time, it can cause the chip's power and ground voltage levels to shift, relative to the circuit board's power and ground levels. The size of the difference depends on the inductance between the chip and board, i.e. the inductance of the chip's power and ground pins. Inductance can be minimized by con…
You're implying it could be done if whatever load distribution and power condition that's done outside of the chip, which consists of a lot of analog components to help manage rapid changes in power consumption, could be somehow packaged inside the chip. So, in rough terms, the internals of a large-scale chip are not one big integrated circuit, but a large number of smaller modules that are massively interconnected,…
I think it depends on the chip's speed. The problem is with rapid changes in current. Of course, higher currents can also have higher fluctuations.
> With the power voltage dropping below ground, that unless you had a floating ground, that'd be implying reverse flow of current, negative voltage, right? Or are you talking about a non-zero voltage ground?
Suppose the board's ground rail is 0 V and the power rail is at 12 V. The chip's ground voltage might bounce up to 9 and its power down to 8. It does cause reverse currents and other bad effects.