Here's how to appreciate it in terms of the counterfactual: Suppose kinetic energy was E = m|v| instead, linearly dependent on speed |v|. What does that mean for the universe? The traditional Lagrangian is L = 1/2 mv^2 - V(x). This kinetic energy gives a different formula: L = m|v|ln|v|-V(x). Deriving the corresponding equations of motion, you get: p = m(1+ln|v|)sgn(v) ma = |v|F A few things we can note from these fo…
I love the counterfactual approach, thank you!!! I've done plenty of this in pure math and stats, but this is the first time I've seen it applied to physics, and I love it! Thank you! If I saw your derivation when I was 18 years old, who knows, maybe I would have caught the physics bug and went that way, this is super cool!
It's essentially the same argument: the Lagrangian can't have a bare a) position or b) velocity vector or it would violate homogeneity or isotropy of space, respectively.