Deja Vu. I read this article a few days ago I'm sure, word-for-word, but it wasn't on this site in OP? It stood out because when it mentioned textbooks and said "including ours" I looked at the site and thought to myself "they do textbooks?".
Faster Than Dijkstra?
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Re: Faster Than Dijkstra?
#12Supposing one uses a 'trie' as a priority queue, the inserts and pops are effectively constant.
Re: Faster Than Dijkstra?
#13Interestingly sorting is O(N) for a surprisingly large class of datatypes. Anything that behaves well with lexicographic sorting really. Supposing one uses a 'trie' as a priority queue, the inserts and pops are effectively constant.
(There's also the problem of how you define your computational model. You can do better than O(n log n) in transdichotomous models. I'm assuming the hand-wavy, naive model the average algorithms class goes along with.)
Re: Faster Than Dijkstra?
#14I struggle to see the point. The paper in question doesn't claim to be practically faster or to want to "replace" Dijkstra, they are just saying "we got a better big-O" and I don't see any reason to doubt they're wrong about that. It's actually common for algorithms with a lower asymptotic complexity to be worse in practice, a classic example is matrix multiplication. Also please, please, can we stop with the "eww, m…
The Quanta article on the paper was considerably more breathless in describing a fine piece of work in mathematics. The author here points out that one of the things that makes Dijkstra's result iconic is that it could be used practically in a straightforward way. As an engineer, beautiful mathematics is useless if I can't convert it to running code.
e.g Two body gravity I can just do the math and get exact answers out. But for N> 2 bodies that doesn't work and it's not that I need to think a bit harder, maybe crack out some graduate textbooks to find a formula, if I did hopefully the grad books say "Three body problem generally not amenable to solution". I will need to do an approximation, exact answers are not available (except in a few edge cases).
Re: Faster Than Dijkstra?
#15Interestingly sorting is O(N) for a surprisingly large class of datatypes. Anything that behaves well with lexicographic sorting really. Supposing one uses a 'trie' as a priority queue, the inserts and pops are effectively constant.
Only if you assume a finite alphabet and bounded length. Relax either and you're back to O(n log n) for a fully general solution. Examples of both: tuples and strings. (There's also the problem of how you define your computational model. You can do better than O(n log n) in transdichotomous models. I'm assuming the hand-wavy, naive model the average algorithms class goes along with.)
The transdichotomous model looks interesting.
Re: Faster Than Dijkstra?
#16Deja Vu. I read this article a few days ago I'm sure, word-for-word, but it wasn't on this site in OP? It stood out because when it mentioned textbooks and said "including ours" I looked at the site and thought to myself "they do textbooks?".
Indeed: https://systemsapproach.org/books-html/
If you are cheap on money, but you do have time, and like to get into networking, I can only highly recommend https://book.systemsapproach.org/
Re: Faster Than Dijkstra?
#17Re: Faster Than Dijkstra?
#18https://youtu.be/3ge-AywiFxs?si=TbcRsBNkzGhpOxQ4&t=842
(timestamped=) He shows a derivation that at best, a sorting algorithm can do is O(n log(n)) for n real positive numbers.
Re: Faster Than Dijkstra?
#19Earlier quoted context omitted.
Only if you assume a finite alphabet and bounded length. Relax either and you're back to O(n log n) for a fully general solution. Examples of both: tuples and strings. (There's also the problem of how you define your computational model. You can do better than O(n log n) in transdichotomous models. I'm assuming the hand-wavy, naive model the average algorithms class goes along with.)
In the most extreme case of this, you can use Counting Sort. Tangential to this, Spaghetti Sort makes me wonder about which parts of CS (especially the data structures, like arrays) are objective or just accidental. The transdichotomous model looks interesting.
The unstated implication is that the theory tracks with real world behavior. This is more or less the case for simple problems: your O(n^2) algorithm won't scale, your database query without an index will take forever and so on, it's definitely a useful and high-signal way of thinking about computational problems.
Obviously modern hardware isn't much like a 70s machine and things like "all memory accesses are O(1)" are so wrong it's not even funny.
It's a pure thought experiment with no possible counterfactual, but I think if you tried to develop basic CS theory from a purely mathematical angle (e.g. consider a machine defined so and so with basic operations costing 1, let's run with this ball without caring much about the real world) you'd naturally end up with some (but not all) of the concepts we're used to. For example, arrays and buffers are very natural. We need more space than our basic unit of memory can accomodate, let's use several in a row. Pointers also follow very nicely, and with them structures like linked lists. Other stuff like B-trees and to some extent hash-tables and friends very much less so, they're definitely "imported" from real-world usage.
Re: Faster Than Dijkstra?
#20Interestingly sorting is O(N) for a surprisingly large class of datatypes. Anything that behaves well with lexicographic sorting really. Supposing one uses a 'trie' as a priority queue, the inserts and pops are effectively constant.
Only if you assume a finite alphabet and bounded length. Relax either and you're back to O(n log n) for a fully general solution. Examples of both: tuples and strings. (There's also the problem of how you define your computational model. You can do better than O(n log n) in transdichotomous models. I'm assuming the hand-wavy, naive model the average algorithms class goes along with.)
You can generally reduce the problem to a finite alphabet by taking the finite subset that actually appears in the input.
If you have an unbounded length then you can make sorting O(l n) where `l` is a bound on the lengths of your input. It's still linear in n, and also better than the O(l n logn) you would with traditional comparison based algorithms once you factor in the O(l) complexity of the comparison function for such elements.