Reminds me of a cool proof I saw recently that there are two numbers a and b such that a and b are both irrational, but a^b is rational: Take sqrt(2)^sqrt(2), which is either rational or not. If it's rational, we're done. If not, consider sqrt(2) ^ (sqrt(2) ^ sqrt(2)). Since (a^b)^c = a^bc, we get sqrt(2) ^ (sqrt(2))^2 = sqrt(2)^2 = 2, which is rational! It feels like a bit of a sleight of hand, since we don't actual…
A joke in approximating numbers raised to irrational powers
31–40 of 44 posts
Re: A joke in approximating numbers raised to irrational powers
#32Earlier quoted context omitted.
pi = 3.2 (that is an assignment statement) https://en.wikipedia.org/wiki/Indiana_pi_bill
My aero engineering friend from university winds me up every time I see him saying that pi = 22/7 - I finally stopped getting angry, checked and it’s pretty good! I’m still glad he didn’t decide to design planes after he graduated though!
Re: A joke in approximating numbers raised to irrational powers
#33sin x = x Half the problems in EE become trivial once you learn this. Sometimes the universe does a bad job of complying with the approximation though.
Are you familiar with the Taylor series? That's the first organ of the Taylor series, something like two decades ago I checked how accurate it goes past 20 organs: https://dotancohen.com/eng/taylor-sine.php
Guessing that "organ" is a typo for "order", but somehow I kind of like envisioning Taylor series as living organisms, with terms being individual organelles.
Thanks for the smile in the morning.
Re: A joke in approximating numbers raised to irrational powers
#34Earlier quoted context omitted.
I wonder what the easiest to prove example of a, b irrational with a^b rational is? The easiest I can think of offhand would be e^log(2). To prove that we need to prove that e is irrational and the log(2) is irrational. To prove log(2) is irrational one approach is to prove that e^r is irrational for rational r != 0, which would imply that if log(2) is rational then e^log(2) would be irrational. To prove that e^r is…
> To prove that e^r is irrational for irrational r You mean for rational r, don’t you?
Re: A joke in approximating numbers raised to irrational powers
#35Happy to see someone else who watches Michael Penn videos.
I came here to say the same thing! YouTube has become a fantastic place for this long tail of content, in this particular case a bunch of interesting math problems and tricks presented on a blackboard. Or, even full classes, from a person focused on honing pedagogy. 3blue1brown is another amazing channel for math as well. I have a feeling that this sort of content is the seeds of very great things for humanity. In th…
Re: A joke in approximating numbers raised to irrational powers
#36Earlier quoted context omitted.
Are you familiar with the Taylor series? That's the first organ of the Taylor series, something like two decades ago I checked how accurate it goes past 20 organs: https://dotancohen.com/eng/taylor-sine.php
> That's the first organ of the Taylor series Guessing that "organ" is a typo for "order", but somehow I kind of like envisioning Taylor series as living organisms, with terms being individual organelles. Thanks for the smile in the morning.
Re: A joke in approximating numbers raised to irrational powers
#37One interesting result implies that numbers like 3^(sqrt(3)) will be transcendental (ie no polynomial will evaluate them to 0). https://en.wikipedia.org/wiki/Gelfond%E2%80%93Schneider_theo...
Small but important correction: no polynomial with integer coefficients (equivalently, rational coefficients). p(x) = (x - 3^(sqrt(3))) is a perfectly fine polynomial with real coefficients.
Re: A joke in approximating numbers raised to irrational powers
#38Reminds me of a cool proof I saw recently that there are two numbers a and b such that a and b are both irrational, but a^b is rational: Take sqrt(2)^sqrt(2), which is either rational or not. If it's rational, we're done. If not, consider sqrt(2) ^ (sqrt(2) ^ sqrt(2)). Since (a^b)^c = a^bc, we get sqrt(2) ^ (sqrt(2))^2 = sqrt(2)^2 = 2, which is rational! It feels like a bit of a sleight of hand, since we don't actual…
e^(i theta) = cos theta + i sin theta (Euler's identity) thus e^(i pi) = cos pi + i sin pi = -1 + i(0) = -1
We know that e and i pi are irrational (in fact i pi isn't even a real) and -1 is rational.
Therefore there exist two numbers a and b such that both a and b are irrational but a^b is rational.
In fact log of just about anything is irrational so e^(log x) works as well for just about all rational x, but Euler's identity is cool so I wanted to use that.
Re: A joke in approximating numbers raised to irrational powers
#39Earlier quoted context omitted.
> That's the first organ of the Taylor series Guessing that "organ" is a typo for "order", but somehow I kind of like envisioning Taylor series as living organisms, with terms being individual organelles. Thanks for the smile in the morning.
No Taylor liked to communicate the series musically on various organs. IT got expensive and that’s why noone ever goes beyond the first two or three terms.
Re: A joke in approximating numbers raised to irrational powers
#40Earlier quoted context omitted.
> That's the first organ of the Taylor series Guessing that "organ" is a typo for "order", but somehow I kind of like envisioning Taylor series as living organisms, with terms being individual organelles. Thanks for the smile in the morning.
No Taylor liked to communicate the series musically on various organs. IT got expensive and that’s why noone ever goes beyond the first two or three terms.