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Interstellar movie black hole implemented with Einstein's equations in C++

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Re: Interstellar movie black hole implemented with Einstein's equations in C++

#91

Earlier quoted context omitted.

>It's quite easy, using a jet aircraft, to (via a ballistic trajectory) get into space A jet engine requires atmosphere. Spaces requires no (or very little) atmosphere. The edge of space is usually defined at 100km (the Karman line). The highest altitude reach by an air breathing jet is around 37km. https://en.wikipedia.org/wiki/Flight_altitude_record A scramjet might get to ~75km according to: https://aviation.stack…

That's the point at which the jet stops working, but by that point you can be going quite fast . If there isn't enough air to run the jet engine, there also isn't enough air to slow you down (much).

Assuming no air resistance and 10m/s^2 gravity. I calculate that you would have to be doing ~1,100m/s (~mach 3.2 at sea level) straight up at 37km to reach 100km. Or ~1,600m/s (~mach 4.7 at sea level) at 45 degrees to perpendicular.

Re: Interstellar movie black hole implemented with Einstein's equations in C++

#92

Earlier quoted context omitted.

Um actually… Chris Nolan doesn’t shoot digital. His more recent pictures (Interstellar included) are shot on a mixture of 35mm, 70mm and IMAX 70mm (!)

What's the difference between 70mm and IMAX 70mm? Is it just the aspect ratio (2.20:1 vs 1.43:1)?

Yes, it’s an even larger format than traditional 70mm. The cells are physically larger. Anecdote: Nolan worked with Kodak to invent black & white IMAX film for Oppenheimer.

https://www.kodak.com/en/motion/blog-post/oppenheimer/

Re: Interstellar movie black hole implemented with Einstein's equations in C++

#93

Earlier quoted context omitted.

Um actually… Chris Nolan doesn’t shoot digital. His more recent pictures (Interstellar included) are shot on a mixture of 35mm, 70mm and IMAX 70mm (!)

What's the difference between 70mm and IMAX 70mm? Is it just the aspect ratio (2.20:1 vs 1.43:1)?

The film is run through the camera & projector sideways, allowing for a larger frame to be laid down on the same stock.

https://secureservercdn.net/198.71.233.183/gkz.aeb.myftpuplo...

Re: Interstellar movie black hole implemented with Einstein's equations in C++

#95
post #89
post #87

Earlier quoted context omitted.

The love angle actually makes sense here. There's no technological way to do what needed to be done: find a willing recipient amongst strangers for a message from the impossible. Only because Murph shared a bond she was able to correctly bet on that there was a message and find out what it was. In something everyone else would not even consider.

Nothing is forbidden, until you try to explain it. I come from the perspective that genre is a contract with the audience. Here _Interstellar_ is making a genre error. Take _Star Wars_ for example. You don't need to know how the Force works. There's no suspension of disbelief because you've bought into the genre and its tropes. The Force is everywhere, Luke is atuned to it. We don't need to know anything else mechani…

I'd argue that Interstellar is defying your expectations, but it's hard sci-fi all the way. At no point happens something that's proven to be impossible, and the future is, well, ever unknown to us, and to the viewer.

Re: Interstellar movie black hole implemented with Einstein's equations in C++

#96
post #56

Earlier quoted context omitted.

Is it not? Would you say the Sun was the main star then?

I haven't seen the movie. It looks great (especially the BH), but the plot makes no sense to me and I didn't feel like watching it.

Do yourself a favor and watch it; it’s so, so good.

Re: Interstellar movie black hole implemented with Einstein's equations in C++

#98
post #88
post #21

Earlier quoted context omitted.

It was completely uneven. Cooper sobbing as he listened to years of messages from his family? I wish I could've written that. The twist where Mann activated his beacon because he didn't want to die alone? Solid. We need the gravity equation to get off Earth because the crops are dying? Love can escape a black hole through the tesseract? This is just patent technobabble nonsense. Where _Interstellar_ fails is in expos…

> We need the gravity equation to get off Earth because the crops are dying? The small craft could launch from a planet with twice the Earth’s surface gravity, make it to escape velocity, and meet the Endurance? Why would they need better propulsion than that to leave the planet and build space habitats?

Given enough time and resources, you'd be right, this would be sufficient. But remember the beginning of the movie - they explicitly stated that every year fewer crops could be harvested, which meant that most people had to work in food production, no matter what they did before. It was also stated that the population wouldn't accept spending going to interplanetary exploration instead of food production - they'd rather survive a little longer than to try and fulfill an impossible goal, or just to have a couple of people survive on ships/stations for a couple years longer, without any hope for long-term survival.

Under these circumstances (only a couple years left until starvation begins & no existing industry) it seems absolutely realistic that the government is able to throw together one hailmary in secret, without also being able to scale production up to save most people before they starve. Remember, the goal of the mission wasn't to measure the data they need to finish their equations, it was to send out one single ship that could continue human civilization on an inhabitable planet.

Had the future humans not intervened (by placing the black hole near inhabitable planets), humanity on earth would have died.

Re: Interstellar movie black hole implemented with Einstein's equations in C++

#100

Earlier quoted context omitted.

That's the point at which the jet stops working, but by that point you can be going quite fast . If there isn't enough air to run the jet engine, there also isn't enough air to slow you down (much).

Assuming no air resistance and 10m/s^2 gravity. I calculate that you would have to be doing ~1,100m/s (~mach 3.2 at sea level) straight up at 37km to reach 100km. Or ~1,600m/s (~mach 4.7 at sea level) at 45 degrees to perpendicular.

Seems about right. https://en.wikipedia.org/wiki/Project_HARP (1966) got 2100m/s from a ground-based cannon: this got the projectile to 179km.
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