BB(3, 4) > Ack(14)
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BB(3, 4) > Ack(14)
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Re: BB(3, 4) > Ack(14)
#2Re: BB(3, 4) > Ack(14)
#3Re: BB(3, 4) > Ack(14)
#4Re: BB(3, 4) > Ack(14)
#5Re: BB(3, 4) > Ack(14)
#6Can someone point me to some resources as to how to interpret the table, which I assume is some sort of description for a Turing machine?
The cell in the table describes which actions to perform. The first row & first column has "1RB" which means: "replace the symbol on the tape with '1', shift 1 symbol to the right on the tape and switch to state 'B'".
The state 'Z' corresponds to the halting state.
Re: BB(3, 4) > Ack(14)
#7Can someone point me to some resources as to how to interpret the table, which I assume is some sort of description for a Turing machine?
Re: BB(3, 4) > Ack(14)
#8Can someone point me to some resources as to how to interpret the table, which I assume is some sort of description for a Turing machine?
[0] https://bbchallenge.org/story#turing-machines
[1] https://en.wikipedia.org/wiki/Turing_machine#Formal_definiti...
[2] https://bbchallenge.org/1RB3LB1RZ2RA_2LC3RB1LC2RA_3RB1LB3LC2...
Re: BB(3, 4) > Ack(14)
#9Re: BB(3, 4) > Ack(14)
#10 0 1 2 3
A 1RB 3LB 1RZ 2RA
B 2LC 3RB 1LC 2RA
C 3RB 1LB 3LC 2RC
with the triple (t',d, s') in row s column t specifying the transition from state s with symbol t under the tape head. the machine overwrites symbol t with t', moves the tape Left/Right according to direction d, and changes state from s to s', halting if s'==Z.This is 3*4*log2(4*2*log2(4+1)) or about 64 bits of information. Meanwhile, in only 49 bits, BBλ(49) far exceeds Graham's number [1].