Drone footage of fledging penguins jumping off cliff
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Re: Drone footage of fledging penguins jumping off cliff
#12Its interesting how unskilled nature can be and still get away with it (here I guess to the thick fur/skin/fat below). If humans would jump from such height so badly, many injuries and possibly few deaths would be happening. I've done my fair of jumps in Swiss swimming pools / beaches where 10m jumping board is standard equipment, and even slightly incorrect landing can be quite brutal on the body. Falling ie on the…
Re: Drone footage of fledging penguins jumping off cliff
#13How is this related to tech and hacking or anything with innovation?
Re: Drone footage of fledging penguins jumping off cliff
#14How is this related to tech and hacking or anything with innovation?
Nature/science meets technology/science.
I found this fascinating.
Re: Drone footage of fledging penguins jumping off cliff
#15Re: Drone footage of fledging penguins jumping off cliff
#16How is this related to tech and hacking or anything with innovation?
Re: Drone footage of fledging penguins jumping off cliff
#17Re: Drone footage of fledging penguins jumping off cliff
#18Re: Drone footage of fledging penguins jumping off cliff
#19Given this video is taken by a drone, and drones are very noisy, are the splashing sounds and sounds of penguins chirping added later?
Re: Drone footage of fledging penguins jumping off cliff
#20[flagged]
Sources
omnicalculator.com favicon wikihow.com favicon View 2 more Answer The terminal velocity of an average-sized penguin falling head-first can be calculated as follows: Assuming an average penguin weight of 5 kg and a cross-sectional area of 0.1 m^2, with a drag coefficient of 0.8 for a streamlined, head-first orientation: Terminal velocity, v_t = √((2 × m × g) / (ρ × A × C_d)) Where:
m = mass of penguin = 5 kg
g = acceleration due to gravity = 9.8 m/s^2
ρ = density of air = 1.225 kg/m^3
A = cross-sectional area = 0.1 m^2
C_d = drag coefficient = 0.8
Plugging in the values:
v_t = √((2 × 5 kg × 9.8 m/s^2) / (1.225 kg/m^3 × 0.1 m^2 × 0.8))
v_t = √(98 / 0.98)
v_t = √100
v_t = 10 m/s Therefore, the terminal velocity of an average-sized penguin falling head-first is approximately 10 m/s or 36 km/h.1345Wolframalpha: https://www.wolframalpha.com/input?i2d=true&i=Subscript%5Bv%...