Earlier quoted context omitted.
They can launch payloads that bring in revenue while working on that problem. There is a good chance they put a bunch of Starlinks on the next flight.
Exactly, they’ve reached feature parity with large expendable launch systems so they can piggyback paying customers with a high risk threshold (starlink) on flights they’d be doing anyways. Given their cadence this phase won’t last long, they’ll likely achieve at least one successful landing next flight.
Starship's Third Flight Test [video]
181–190 of 413 posts
Re: Starship's Third Flight Test [video]
#182I was just watching Spacex official stream and at ignition they switched to Musk hawking cryptocurrency. What just happened?? edit: wild I just realized take off is 50 minutes from now... what had I been watching?? they did a countdown and there was ignition... was that a time wrap? Am I going insane? edit2: @spacex034 is not @spacex... today I learned...
There's a fake SpaceX YouTube account that looks official because they included videos from the real channel in playlists to get verification ticks & have managed to harvest thousands of subscribers. YT's interface is a bit dumb for including the verification ticks in that use-case.
That is not how it happens. The account is verified because it is a stolen account that had lots of subscribers & views. They hide/delete the existing videos & rebrand the channel. It famously happened to Linus Tech Tips last year after a staff member fell for a spear phishing attempt.
Re: Starship's Third Flight Test [video]
#183Earlier quoted context omitted.
Parent's (correct) point is that it isn't a matter of the ascent trajectory. They can't leave the Starship up in orbit, and where it reenters needs to be controlled.
> They can't leave the Starship up in orbit, and where it reenters needs to be controlled. Why? Plenty of boosters re-enter uncontrolled and burn up all the time.
Re: Starship's Third Flight Test [video]
#184The test is essentially a success at this point. Starship can take payload to orbit and open/close the payload doors. The remaining things are icing on the cake. They can refine re-usability while flying payloads.
Re: Starship's Third Flight Test [video]
#185Earlier quoted context omitted.
Technically it's a transatmospheric orbit. That is, an orbit such that it'd stay up there if the atmosphere were not present. The difference between this and full orbit is just a few seconds longer burn, so it's a difference with little meaning in terms of proving out the ability to reach orbit.
I don't believe that's the case—see the math in my sibling comment.
I'm not really in a place to judge your math right now to really add anything on that.
Re: Starship's Third Flight Test [video]
#186Re: Starship's Third Flight Test [video]
#187Earlier quoted context omitted.
I did the math. So, the minimal orbit at 180 km, the one that grazes the earth's surface at its perigee, is about 7.75 km/s or 27,900 kph. The other commenters are right: it was never technically orbital. edit: (let* ((μ 398600.0) ;; km^3/s^2 (r 6371.0) ;; km (peri (+ r 0.0)) (apo (+ r 180.0)) (a (* 0.5 (+ peri apo)))) (sqrt (* μ (- (/ 2.0 apo) (/ 1.0 a))))) ;; 7.745844595118488
That is really cool. For those of us that are space nerds but don't have the depth of understanding, do you mind walking us through the calculation above?
In the form I'm using, I'm using standard parameters of an elliptical orbit: the periapsis (the closest approach to the center of mass of the massive body (which is a focal point of the ellipse which the orbit traces)), apoapsis (farthest distance), and semimajor axis (their arithmetic mean [1]). I'm evaluating the orbital velocity at the highest point, the apoapsis. μ is a short form for the product G*M, the standard gravitational parameter [2] of Earth (which is known to much higher precision than either the universal gravitational constant G, or the mass of the earth M, individually).
The particular orbit I'm applying it to is one whose periapsis is equal to the Earth's radius—an orbit that touches the surface of the Earth. This is the dividing line for orbital / suborbital: a suborbital trajectory is one that (mathematically) goes beneath the Earth's surface.
[0] https://en.wikipedia.org/wiki/Vis-viva_equation#Equation
[1] https://en.wikipedia.org/wiki/Semi-major_and_semi-minor_axes...
[2] https://en.wikipedia.org/wiki/Standard_gravitational_paramet...
Re: Starship's Third Flight Test [video]
#188I was just watching Spacex official stream and at ignition they switched to Musk hawking cryptocurrency. What just happened?? edit: wild I just realized take off is 50 minutes from now... what had I been watching?? they did a countdown and there was ignition... was that a time wrap? Am I going insane? edit2: @spacex034 is not @spacex... today I learned...
Re: Starship's Third Flight Test [video]
#189Earlier quoted context omitted.
Parent's (correct) point is that it isn't a matter of the ascent trajectory. They can't leave the Starship up in orbit, and where it reenters needs to be controlled.
> They can't leave the Starship up in orbit, and where it reenters needs to be controlled. Why? Plenty of boosters re-enter uncontrolled and burn up all the time.
Re: Starship's Third Flight Test [video]
#190Earlier quoted context omitted.
Nevermind
The latest Soyuz revision is ~$50m per launch, it has a payload less than half of a Falcon 9 that lands on a droneship, and ~2/3rd of a Falcon 9 that returns to launch site. Making it twice the cost per kg. The highest flight rate it has ever achieved has been 2/month. It has a 96% success rate. The latest Falcon 9 revision is ~$67m per launch. Lately it flies every ~3 days. Over the past year it has flown ~100 times…
And that is the price, the cost is unknown but likely lower.