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A confusing probability question: Red and green balls in an urn

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Re: A confusing probability question: Red and green balls in an urn

#51
The mathematical term for this is a "Laplacian urn" and the probability is governed by https://en.wikipedia.org/wiki/Rule_of_succession

In this specific case, P(redOnKthSample) = (numberOfRedSamples + 1) / (totalNumberOfSamples + 2) = (1+1)/(1+2) = 66% red.

On the second draw, if the ball is green, then you get P(redOnThirdSample) = (1 + 1) / ( 2 + 2) = 50%

Re: A confusing probability question: Red and green balls in an urn

#52
post #23

Earlier quoted context omitted.

More likely than the other option, given the information. Getting an accurate grasp on the information is the whole point of the question.

Why is that the question? Why not "more likely than the last draw" ?

If, hypothetically, the majority of words communicated from one homo sapiens to any other homo sapiens (majority weighted by the number of homo sapiens who will hear, read, or otherwise receive the word over the course of the word's existence) were designed to be precise and unambiguous to the extent that the mean number of homo sapiens who receive the word correctly interpret the exact meaning of the word intended by the entity that chose the word is greater than 99.99%, then I would estimate a greater than 90% probability that the cumulative unique information (in the information-theoretic sense) contained in communications correctly interpreted by the receiving homo sapiens on any given day would be less than the cumulative unique information that is currently being correctly interpreted today (January 30th 2024 in the Gregorian calendar), and furthermore the reduction in information thus communicated would have a negative effect on progress towards the majority of cumulative goals implicitly created by all living homo sapiens.

Or I could just say "I think most people interpreted the tweet correctly, and it would be annoying if it was overly precise"

Re: A confusing probability question: Red and green balls in an urn

#53
post #31

Earlier quoted context omitted.

That's definitely fair, and I assuming in a classroom setting you'd be very consistent and precise about what that means. But this is a twitter poll, and I doubt people are that consistent. Ultimately I'm just pushing back on the conclusion that this is because "Bayesian thinking is really foreign to people." I think if the question had instead been "would you bet on the urn having started out with more red balls, gr…

That question is quite a bit of handholding. A closer analogue would be “would you bet the next ball is red / green / they’re equally likely?”. Personally I’d word it as “The next ball is… more likely to be red than green / more likely to be green than red / equally likely to be red or green / I don’t know.”

But isn't that exactly how it is worded? Just showing it a bit?

Re: A confusing probability question: Red and green balls in an urn

#54

Earlier quoted context omitted.

I'd argue that it's not so much a difference of opinion than it is just a reasoning error given the question as stated. That's sort of the whole point of this post-- this is a case where "doing the math" in the expected way gives the wrong answer, because the state of the system is cast in stone (in terms of the ratio of red/green balls in the urn) when you first start out, so it's all about leveraging the informatio…

It's definitely a poorly worded question. "More likely" is ill-defined. More likely than what? Than the last draw? Than drawing the other color just on this pick?

How is "more likely"I'll defined? They are two options red or green. Are you more likely to draw red or are you more likely to draw green.. how is it poorly worded?

Re: A confusing probability question: Red and green balls in an urn

#55

I think the wording is also biasing the outcome. The next ball is more likely to be green than the previous ball , and a lot of people will regard that posterior probability statement as implicit. If the question had been phrased differently eg, 'what is the most likely color for the next ball selected' I suspect more people would have voted for equal likelihood.

What does the previous ball have to do with it? We KNOW the previous ball is red. Then it asks "more likely to be red" It seems pretty obvious that it is saying draw the next ball, which is more likely? Red, green, equal. Why would you think it is comparing the second pick probability to the first pick probability?

Re: A confusing probability question: Red and green balls in an urn

#56
post #20

It's as ill posed as the Monty Hall problem. The issue is in what it means for the first ball to picked randomly. Would the question be valid if the first ball was green? If not, then it's equivalent to the standard answer to the Monty Hall problem. Analyze it as if the first ball was not picked randomly (i.e. Monty intentionally picked the wrong door).

I'm not sure why you think it is ill posed. The question is, you randomly pick a ball, IF it is red then... So yeah, it is basically the same as "someone else removes a red ball" now randomly select a ball. OR Pick a ball, is the color of the second ball more likely to be the same as the first, different, or equal. That is really the question here.

edit: After thinking about it some more, it is NOTHING like handing the bag to someone else and having them remove a red ball. The whole point to the first draw is to draw the ball randomly. I think my second statement is still true. But to your original question, if the first ball isn't red, then the question is invalid (and you can't throw the ball in and choose again)

Re: A confusing probability question: Red and green balls in an urn

#57
post #8
post #6

Follow up question: > You are given an urn containing 100 balls; n of them are red, and 100-n are green, where n is chosen uniformly at random in [0, 100]. You select 99 balls at random and find that they are all red. What is the probability the last ball is red?

50%. With current knowledge N is either 100 or 99 with an equal probability.

[deleted]

Re: A confusing probability question: Red and green balls in an urn

#58
My first thought on this is, half the time there will be more red balls in the container. IF you draw a red ball first, you are more likely to be in the half that had more red balls. Therefore you are more likely to draw a second red ball. Yes, a small percent of the time you will be in the case that there are more green balls (maybe you got unlucky and pick the 1 red ball!) So my guess is that it isn't a huge percent higher, but it is more likely to be a red ball.

Re: A confusing probability question: Red and green balls in an urn

#59
post #52

Earlier quoted context omitted.

Why is that the question? Why not "more likely than the last draw" ?

If, hypothetically, the majority of words communicated from one homo sapiens to any other homo sapiens (majority weighted by the number of homo sapiens who will hear, read, or otherwise receive the word over the course of the word's existence) were designed to be precise and unambiguous to the extent that the mean number of homo sapiens who receive the word correctly interpret the exact meaning of the word intended b…

'What is the most likely color for the next ball selected?'.

Try this book out, it's a fun read on how minor changes in words can make big differences in readability: https://www.amazon.com/Sense-Style-Thinking-Persons-Writing-...

Re: A confusing probability question: Red and green balls in an urn

#60

Earlier quoted context omitted.

It's definitely a poorly worded question. "More likely" is ill-defined. More likely than what? Than the last draw? Than drawing the other color just on this pick?

How is "more likely"I'll defined? They are two options red or green. Are you more likely to draw red or are you more likely to draw green.. how is it poorly worded?

Because it could be more likely red than green, or more likely red than it was likely that the first choice was red (which is where some people got confused, they thought the question was asking about the relative chances of red on the first choice v second choice), more likely green than the first one was likely to be green(same basic problem).
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