Notes on a few abnormalities in analysis (2022)
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Notes on a few abnormalities in analysis (2022)
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Re: Notes on a few abnormalities in analysis (2022)
#2> Things fall apart when the space is not compact. Your sequences may converge but not to an element in your space.
This is about closedness only. ℝ is not compact but contains its limit points.
Re: Notes on a few abnormalities in analysis (2022)
#3> Things fall apart when the space is not compact. Your sequences may converge but not to an element in your space. This is about closedness only. ℝ is not compact but contains its limit points.
Yep. The reason compact spaces are nice is because compactness lets you reduce something that's infinite to something that's finite.
Re: Notes on a few abnormalities in analysis (2022)
#4> Things fall apart when the space is not compact. Your sequences may converge but not to an element in your space. This is about closedness only. ℝ is not compact but contains its limit points.
It could be that the author was thinking about sequential compactness: every sequence of elements of the space has a convergent subsequence (with its limit also in the same space).
For metric spaces, sequential and usual compactness coincide:
Re: Notes on a few abnormalities in analysis (2022)
#5Gelbaum-Olmsted Counterexamples in analysis is a standard reference for various pathological examples in analysis:
Re: Notes on a few abnormalities in analysis (2022)
#6> Things fall apart when the space is not compact. Your sequences may converge but not to an element in your space. This is about closedness only. ℝ is not compact but contains its limit points.
Yes, but not every sequence in R converges.
That's of course also true of a compact space, the author was being imprecise there. What they meant was definitely sequential compactness, as mentioned by a sibling comment.
Re: Notes on a few abnormalities in analysis (2022)
#7Cantor's set always messes with my mind.
Say you start with the standard construction: take closed interval [0, 1], then remove open middle third, then remove two open middle thirds from two remaining segments, then remove 4 open middle thirds from 4 remaining segments, etc countably many times (more formally, intersect all of the sets you obtain in each of the step).
Intuitively, what remains should be the end points of the removed intervals, but this is not true: since at every step you removed finitely many intervals, and there were countably many steps, you removed finitecountable countable = countably many intervals, so there are only countably many many ends of removed intervals, but the Cantor's set is uncountable. So where do the remaining points come from?