Earlier quoted context omitted.
The obvious dumb classical algorithm for simulating a quantum computer with n qubits runs in O(2^n) time and space. Since 2^log(n) = n is polynomial it follows that "log-space" quantum circuits, I.e. quantum circuits with a logarithmic number of qubits are efficiently classically simulable. These log-space circuits are an obvious "island" in the metaphor of the article and adding more qubits is the "quantum resource…
Would be incorrect to consider the example where there is no superposition like a special case of the island with no entanglement? Because you should be able to classically simulate superposed states as long as these are not entangled so states with no superposition should be a particular subset.
I think you can sort-make the argument you want to make, because all computational basis states are also product states, just like all computational basis states are also stabilizer states and also (if they have the right parity) fermionic gaussian states. Where it goes wrong is when you start thinking about gates/circuits instead of states, because (e.g.) CX or CCC..CX gates with arbitrary numbers of controls are (in general) highly entangling gates, but they map computational basis states to other computational basis states.
Does this make sense?