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Why isn't Titan classed? (2019)

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Re: Why isn't Titan classed? (2019)

#301

Earlier quoted context omitted.

"even NASA" implies that NASA is the objective paragon of software development. There are many ways to develop software, and while I have never worked for NASA I can virtually guarantee that their development process is not the same as some random web service. I've found that it's better to think of unit tests as a contract. You don't write them to check your code for bugs, you write them to declare an explicit (thou…

>> "even NASA" implies that NASA is the objective paragon of software development. Sure. They have some of the highest costs of failure post-deployment of anyone, and they have some solid development practices. I'll cite NASA in this context any time. Feel free to pull in other sources if you don't like them though.

I never said or implied they have poor development practices.

But the constraints, requirements, and priorities for a given project at NASA won't even be the same as every other project there, let alone projects at pretty companies in different fields.

By extension, I would argue that the concept of universally superior development best practices as a whole doesn't make sense.

Re: Why isn't Titan classed? (2019)

#302

Earlier quoted context omitted.

Separate from the comments about pressure differential - even 2 atmospheres is probably enough to risk decompression sickness if they just popped the hatch at the end of the dive. So you'd need some way to reduce the pressure gradually. That either needs a way to vent gas out (which means adding a hole in the hull, which you'd really rather avoid having to deal with), or having a compressor inside the hull, or do the…

I'm not sure why it seems intuitive to me that the external to internal pressure ratio would be the measure of force exerted... i.e. that 2psi vs 1 would have the same net force as 100 vs. 50. I guess it's wrong, hence the responses, but it's still bothering me. Like, it seems intuitive that twice the mass in the same volume should exert twice the force on the inside of the container. I don't completely understand my…

Pressure is Force / Area.

The materials must resist the net pressure, which is a vector addition, not division of vector's magnitudes one by another.

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