I'd like a physics analysis of how flat/hard a surface you need to roll a D65536, how long it would take to settle, and how good a microscope you'd need to read the top face. Is there, like, 99designs for physics questions? I'd happily pay $99 for the answer, then post it here like I worked it out myself.
a 1ft diameter d65536 could be broken into surfaces with area 4.45 square millimeters, or a little over 2x2mm. With good eyes and enough squinting, a microscope might not be needed. maybe fill it with liquid with a tiny air bubble to find the top face 1in diameter, however, gives 0.175mmx0.175mm per face, or about the width of a hair by the width of a hair.
The cursed d65536
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Re: The cursed d65536
#62Earlier quoted context omitted.
No.
Why? Is it because it haven't been found, or is there a proof of impossibility?
Re: The cursed d65536
#63Earlier quoted context omitted.
a 1ft diameter d65536 could be broken into surfaces with area 4.45 square millimeters, or a little over 2x2mm. With good eyes and enough squinting, a microscope might not be needed. maybe fill it with liquid with a tiny air bubble to find the top face 1in diameter, however, gives 0.175mmx0.175mm per face, or about the width of a hair by the width of a hair.
I wonder how much bias engraving or even painting the numbers on the die would introduce? The weight of "1" will be noticeably different to "58888".
Re: The cursed d65536
#64Re: The cursed d65536
#65Re: The cursed d65536
#66Earlier quoted context omitted.
This sounds interesting - could you elaborate further on how rejection sampling "fails" on LuaJIT?
I mean, as far as correctness as concerned, of course it works, but performance-wise in a raytracer I was toying around with it was a dismal failure compared to the (traditionally shunned) analytic approach. The issue, as far as I understand it, is that LuaJIT only handles traces of two shapes: linear code; or linear loop prologue followed by linear loop body. The conditions of any branches (that could not be determi…
Re: The cursed d65536
#67> This is of course hilariously cursed. It will look almost perfect, but very rarely give numbers outside the expected range. If the D65538 is fair, it is usable: you just discard the two unwanted values when they show up and roll again. Those faces could be labelled as "roll again". If you have a uniform source of random numbers from 1 to N, you can get a uniform distribution from 1 to M < N simply by discarding val…
even better, you can round the top and bottom. Either by semi spheres or pointy like a pencil tip. Then chances of "roll again" hitting would be really low!
Re: The cursed d65536
#68> This is of course hilariously cursed. It will look almost perfect, but very rarely give numbers outside the expected range. If the D65538 is fair, it is usable: you just discard the two unwanted values when they show up and roll again. Those faces could be labelled as "roll again". If you have a uniform source of random numbers from 1 to N, you can get a uniform distribution from 1 to M < N simply by discarding val…
Although hex D16s would probably be better.
D20s with 0-F plus two extras could be pretty awesome in a cyberpunk tabletop game. The other two could be "IOError" that makes the matrix glitch in a bad way, and superposition, that makes it glitch in a way you can use.
Re: The cursed d65536
#69https://healpix.sourceforge.io/
You can't make a d65536 with it but you can make a 74^2 * 12 = d65712.
Re: The cursed d65536
#70I'd like a physics analysis of how flat/hard a surface you need to roll a D65536, how long it would take to settle, and how good a microscope you'd need to read the top face. Is there, like, 99designs for physics questions? I'd happily pay $99 for the answer, then post it here like I worked it out myself.
a 1ft diameter d65536 could be broken into surfaces with area 4.45 square millimeters, or a little over 2x2mm. With good eyes and enough squinting, a microscope might not be needed. maybe fill it with liquid with a tiny air bubble to find the top face 1in diameter, however, gives 0.175mmx0.175mm per face, or about the width of a hair by the width of a hair.