My side-project this week has been searching for an optimal Wordle strategy. I figured it would make a great blog post but I haven't got that far yet. Step 1 is to find an optimal starting word. My most insightful finding so far has came from trying to define a cost function for comparing potential starting words. It turns out that "% of potential guesses [not] eliminated" is an excellent loss function. Importantly,…
Since you've been looking into it, how are words with multiple of the same letters treated on Wordle. If there are two (or three) 'E' in the solution or the guess?
If the answer has one E and you guess a word with two Es, only one of the Es will be marked correct (green/yellow). If one of the Es is in the correct place, it will be green and the other one grey. Otherwise the first E will be yellow and the second grey. So if the answer has fewer Es than your guess the game tells you.
If the answer has more Es than your guess there is no indication of this.