I still don't get it. 1. Three doors. 2. Two doors have a goat, and one has a car. 3. The contestant has a 1/3 chance of winning the car? 4. The contestant loses. 5. New game, and odds? 6. There's a 50/50 chance of winning? (I'm assuming Monte Hall has no clue to where the car is. He is just opening doors.) 7. Could someone explain it to me, and thanks in advance. (Off topic but a fawn had two babes in my back yard.…
You have three doors. As you note, you have a 1/3 chance of winning. Monty now reveals a losing door. At this point, your door has a 1/3 chance of still winning - the probability of that choice can’t change. However, as we now know one door has a 0/3 chance of winning (it’s been revealed) the remaining door must have (1-1/3) chance of winning. Thus, the remaining door has a 2/3 chance of winning.
The Time Everyone “Corrected” the World’s Smartest Woman (2015)
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Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#182I'm familiar with the problem and my intuition is still wrong. I wonder if you couldn't design a gambling machine that has a variant of the Monty Hall problem built-in favoring the house (naturally).
Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#183I kinda miss the newspaper, the way it was back then.
Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#184Earlier quoted context omitted.
The other door is not irrelevant. When you first picked a door, there was a 33% chance it was right, and a 67% chance one of the other two doors was right. Once the other door got opened, it is still a 67% chance that the other two doors is right, but you now know which one of those two it would be - the one which wasn’t opened.
Thats what I'm stuck on, I suppose. Imagine the entire situation is reversed. The Reverse Monty Hall problem. I'm given a choice between two doors, once of which contains a car and one contains a goat. I have to choose, 1 or 2. Then the game show host reveals that there was also a third door, which contained a goat, which is no longer relevant and never was relevant. I'm then also asked to choose a door (which is als…
In the original problem, its presence _is_ relevant, as the car could be behind doors 1, 2, or 3. Say you pick door 1 - there's a 1/3 chance you are right.
The host is then left with doors 2 and 3. We know there is a 2/3 chance the car is behind _one_ of these doors. When the presenter reveals a goat (say in door 2), he is reveling information about this set of doors - there is still a 2/3 chance that the car is behind one of the doors in this set, but there's only one door left we don't know anything about (3). There is therefore a 2/3 chance that it is behind _this_ door.
Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#185Earlier quoted context omitted.
I think it's made pretty explicit. In this version: "Then, the host, who is well-aware of what’s going on behind the scenes, opens door #3, revealing one of the goats." The host has to open a door that doesn't show the car.
You're quoting Priceonomic's 2021 description of the problem. This is NOT the 1990 Parade Magazine description of the problem that generated all the responses.
The host's knowledge is explicitly mentioned, and the only purpose this could have is that so he can use it to avoid giving the game away.
Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#186I still don't get it. 1. Three doors. 2. Two doors have a goat, and one has a car. 3. The contestant has a 1/3 chance of winning the car? 4. The contestant loses. 5. New game, and odds? 6. There's a 50/50 chance of winning? (I'm assuming Monte Hall has no clue to where the car is. He is just opening doors.) 7. Could someone explain it to me, and thanks in advance. (Off topic but a fawn had two babes in my back yard.…
Monte Hall DOES have a clue where the car is, and is NOT "just opening doors" With the full knowledge of where the car is, Mr Hall opens a door that is NOT the door the contestant chose, and is also NOT the door containing the car.
Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#187Earlier quoted context omitted.
* Most of all, it's the calculation vs intuition that I like. You can do the calculation, or run simulations and prove correctness.* It puzzles me that so many smart people got it wrong. It’s so easy to check your working. When I first heard of this problem, I got it wrong too. Then I was told the answer, and to prove it to myself, it’s trivial to list the scenarios and simulate on paper. It’s still uncomfortable to…
I think people didn't check because the answer of 50% is so strikingly obvious (despite being wrong) that it seems like there's no work to check.
There is a confirmation bias that people expect people who are aware of the Monty Hall Problem expect others to be wrong about it and attribute it to people not understanding. I think it's perfectly acceptable for someone to read the vague "the host, who is well-aware of what’s going on behind the scenes" and not assume that means he chooses to pick a goat. They're probably right, and the people saying 50% are reasoning along the lines of "there are two doors so 50/50".
For rigor, I think the host's rules need to be more strict: "The host knows what is behind the doors and will never reveal the car".
Or a 50% answer is correct if you lay out the principles of how the host acts given his knowledge.
Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#188If we can’t even mention how STEM women are often treated as default-incompetent in this, _very_ egregious case then we have no hope of being able to have the discussion at all.
Re: The Time Everyone “Corrected” the World’s Smartest Woman (2015)
#189There are a number of things I like about the monty hall problem. There's the history, the unintuitiveness, the subtle easy-to-screw-up nature of probability problems, the calculation, the sociology, and the overconfidence of wrong experts. Most of all, it's the calculation vs intuition that I like. You can do the calculation, or run simulations and prove correctness. In fact, it would be much harder to be so widely…
In this case, though, I don't believe it's just calculation vs. intuition. The reason the 100 or million door problem helped me understand was because it clarified an implicit rule of the game: that the door the host chooses to open is not random . If it were random, it would make for a very boring game ("Uhh, there's the prize, you win, I guess that's game over.") Once I understood that the host would only ever open…