MathJax, beautiful math in all browsers
mathjax.org
MathJax, beautiful math in all browsers
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Re: MathJax, beautiful math in all browsers
#2Re: MathJax, beautiful math in all browsers
#3Re: MathJax, beautiful math in all browsers
#4Re: MathJax, beautiful math in all browsers
#5The documentation page just says "Open Source", the FAQ and download pages nothing at all.
The release announcement at http://www.mathjax.org/2010/01/12/news/mathjax-beta-released... finally says "Apache 2.0 open source license".
Note to other developers: don't hide your license -- it's a piece of information others might actually be interested in, particularly if it's not an application, but more of a library.
Re: MathJax, beautiful math in all browsers
#6[MathJax, on the other hand, looks glorious. Many thanks to the people in charge of the project!]
Re: MathJax, beautiful math in all browsers
#7Doesn't work as i expect in my browser.
Re: MathJax, beautiful math in all browsers
#81. It is so modular that you cannot really optimize it using something like Google Closure (http://code.google.com/closure/ ). If you do, it breaks it.
2. The modularity means that you're likely to need a few roundtrips to the server to get everything. Invariably these block the loading of the page and you get a hang, sometimes for a few seconds. This is not good for user experience.
Of course MathJax solves a very important problem, but it's a problem browsers have introduced. None of the support MathML in a sane way: Firefox requires content served as fully valid XHTML (good luck with that if you're using a CMS) and Webkit only got MathML support recently in the nightly releases. If browsers actually implement MathML in a way developers can use without losing hair, then MathJax is no longer needed. Till then, I love MathJax despite its warts.
Re: MathJax, beautiful math in all browsers
#9Looks nice on the machine I use as a js sandbox, though.
Re: MathJax, beautiful math in all browsers
#10Source of the top equation is: J_\alpha(x) = \sum_{m=0}^\infty \frac{(-1)^m}{m! \, \Gamma(m + \alpha + 1)}{\left({\frac{x}{2}}\right)}^{2 m + \alpha}
Source of the bottom equation is:
c 2 = a 2 + b 2 −2ab cosθ
Browser is Chrome 8.0.552.215 on Windows 7 Ultimate 64-Bit