Earlier quoted context omitted.
No, you are making the same mistake as some of the other people. You are summing a geometric series so you are saying the ball bounces infinitely often and the time it takes for the ball to bounce infinitely often is blah. But if it bounces infinitely often then it never stops to roll on the floor because if it did stop and roll on the floor in a finite amount of time then you wouldn't have an infinite series to sum…
The series is infinite, but the sum of the series can still be finite. These two things are not at odds.
Simple bouncing ball puzzle, with $50 prize
31–40 of 58 posts
Re: Simple bouncing ball puzzle, with $50 prize
#32Earlier quoted context omitted.
Here is a spoiler. Energy = force * distance After each bounce you are left with 60% of its energy, so it comes back up 0.6 times as high as the previous bounce. Distance falling in time t is proportional to the square the time, so each bounce takes sqrt(0.6) times as long as the previous bounce did. Thus the timing of the bounces forms a geometric series. It is well known that the sum of such a geometric series is 1…
Same mistake as everyone else. Geometric series means infinitely many bounces and infinitely many bounces means it never stops bouncing. Everyone is making the same logical fallacy.
Re: Simple bouncing ball puzzle, with $50 prize
#33Earlier quoted context omitted.
I'm more curious to know how many people have sent in incorrect answers. My immediate guess disagreed with my mathematics.
My immediate guess agreed with my mathematics. But I have the advantage that a variant of this problem had occurred to me some 20 years ago, and I worked it out. In fact, pick up a bouncy ball and drop it on a flat surface. You can observe the fact that bounces become smaller and more rapid, and then they stop bouncing entirely. There may be some residual vibration that is not apparent, but it sure seems to act like…
Indeed, I've done that -- but my intuition told me that it was stopping due to friction, not due to the exponential decay of an infinite number of bounces. :-)
It's oddly disappointing to realize that the model actually acts more or less the same as the real world for once.
Re: Simple bouncing ball puzzle, with $50 prize
#34Earlier quoted context omitted.
Same mistake as everyone else. Geometric series means infinitely many bounces and infinitely many bounces means it never stops bouncing. Everyone is making the same logical fallacy.
I refer you to Zeno's paradox for an example of how a geometric series can allow an infinite number of things to happen in a finite time. In this case the time taken forms a geometric series, and the total time taken is the sum of that geometric series. Which means that, for the same mathematical reasons that let Achilles catch the tortoise, it stops in finite time.
Re: Simple bouncing ball puzzle, with $50 prize
#35Earlier quoted context omitted.
The series is infinite, but the sum of the series can still be finite. These two things are not at odds.
Ya, and what are the terms in the series representing? Is it air time of each bounce? Your calculation makes it clear that it is. So you are saying you are calculating the air time for infinitely many bounces, the key word here is infinite , i.e. the ball bounces up and down, up and down infinitely often. So if the ball bounces infinitely often how can it stop and roll on the floor because infinitely many bounces mea…
2) The ball bounces an infinite number of times.
3) This is not a contradiction, no more than the idea that a projectile passes through an infinite number of spatial points in finite time. Please go and read about geometric series and Zeno's paradox on wikipedia, as another commenter has already suggested.
Re: Simple bouncing ball puzzle, with $50 prize
#36Earlier quoted context omitted.
True but then in what order are you calculating things. In order to have an infinite series for the air time to sum you must assume there are infinitely many jumps so if there are infinitely many jumps then the ball never rolls on the floor by definition. But then if you say you sum the infinite series of time intervals and the ball stops at that time then you don't have infinitely many bounces because if there were…
http://en.wikipedia.org/wiki/Geometric_series See also: http://en.wikipedia.org/wiki/Zenos_paradox (Hint: It's not really a paradox.)
Re: Simple bouncing ball puzzle, with $50 prize
#37Earlier quoted context omitted.
Same mistake as everyone else. Geometric series means infinitely many bounces and infinitely many bounces means it never stops bouncing. Everyone is making the same logical fallacy.
You don't give up, do you? An infinite series can have a finite sum. Yes, the ball bounces infinitely often, but it does that in a finite amount of time.
Re: Simple bouncing ball puzzle, with $50 prize
#38Re: Simple bouncing ball puzzle, with $50 prize
#39Earlier quoted context omitted.
You don't give up, do you? An infinite series can have a finite sum. Yes, the ball bounces infinitely often, but it does that in a finite amount of time.
I'm not disagreeing with you. Yes, an infinite series can have a finite sum, no argument there but what I am arguing with is that people are saying the ball stops bouncing after time t = whatever. Everyone is confounding two things here, air time and bouncing. Yes, the air time is finite but the bouncing isn't. So you can't say it stops bouncing after time t = whatever if you calculate t = whatever by assuming infini…
Personally, I call that "not bouncing".
Re: Simple bouncing ball puzzle, with $50 prize
#40The ball has horizontal energy as implied by the parabolic arc. Assuming no friction the ball's horizontal velocity will be constant, hence it will just roll away at whatever initial horizontal velocity it had.
Technically, it will slide, since without friction it can't obtain any angular momentum.