> We’ve now established that if we choose some constant C, then defining division such that x/0 = C does not lead to any inconsistencies. There is no proof in this post that 1/0 = 0 maintains consistency. Rather, it contains refutations of one or two arguments that claim inconsistency, along with appeals to authority.
You're right. It really would've been nice for the author to offer a direct proof. However, while I'm a bit rusty, I think it basically has to be true. For there to be an inconsistency, 1/0 = 0 must either a) imply the negation of some previous theorem of arithmetic or b) imply that 1/0 = x, for x != 0. I think a) can only be true by way of b), since no existing theorem of arithmetic involves the expression y/0 for a…
(a+b)/c = a/c + b/c
(in particular, for C != 1, as the author claimed it would work not just for 0 for for any real number)
Now to say this is true you have to say "unless c = 0", whereas before that was automatic from the definition of division.