Why is this significant?
Because it means that some RSA keys may be weaker than others. Without diving too far into the mathematics of it, the RSA cryptosystem (and indeed, many asymmetric-key cryptosystems) is based on the notion that multiplying two gigantic prime numbers together to get another gigantic non-prime number is easy; but taking a gigantic non-prime number and figuring out which two prime numbers were multiplied together is inc…
While it is true that if we can factor a number that is a composite of two primes is sufficient to break RSA, the security of RSA is based on a weaker property (cf. https://en.wikipedia.org/w/index.php?title=RSA_(cryptosystem...):
Given two prime number p,q >= 3, let n := p * q. Let lambda(n) = lcm(p-1, q-1) (Carmichael's totient function). A public key then is (n,e), where 1 The RSA problem asks that given a c \in {0, ..., n-1}, find an m \in {0, ..., n-1} such that c = m^e mod n.
It is easy to check how this problem becomes simple if we can factor n (then we simply can find the private key). But it is an open problem whether solving the RSA problem is as hard as factoring or not.