An impossibility theorem for gerrymandering
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An impossibility theorem for gerrymandering
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Re: An impossibility theorem for gerrymandering
#2That's why the efficiency gap is so exciting as a measure.
Re: An impossibility theorem for gerrymandering
#3First of all, it seems highly unlikely such a distribution of red and blue votes would occur. But more importantly, blue is a majority of every 3x3 square - why shouldn't it win every district?
Re: An impossibility theorem for gerrymandering
#4Its a solid proposal, but I guess its up to the courts to decide if "Efficiency Gap" is a good metric. I guess I'll be interested in hearing the arguments as they come up.
Re: An impossibility theorem for gerrymandering
#5I'm confused about the example. First of all, it seems highly unlikely such a distribution of red and blue votes would occur. But more importantly, blue is a majority of every 3x3 square - why shouldn't it win every district?
Because we are supposed to have a representative government. If there's 55% Blue voters and 45% Red Voters, you're supposed to ideally have 55% Blue representatives and 45% Red representatives.
The example is a counterexample of this concept. Instead of 55% Blue / 45% Red split, the map as a whole becomes 100% blue. This is almost the very definition of "Tyranny of the Majority".
Re: An impossibility theorem for gerrymandering
#6I'm confused about the example. First of all, it seems highly unlikely such a distribution of red and blue votes would occur. But more importantly, blue is a majority of every 3x3 square - why shouldn't it win every district?
> why shouldn't it win every district? Because we are supposed to have a representative government. If there's 55% Blue voters and 45% Red Voters, you're supposed to ideally have 55% Blue representatives and 45% Red representatives. The example is a counterexample of this concept. Instead of 55% Blue / 45% Red split, the map as a whole becomes 100% blue. This is almost the very definition of "Tyranny of the Majority"…
Re: An impossibility theorem for gerrymandering
#7The data scientist in me wants centroids around circles with fuzzy edges. If we could all agree that fuzzy circles is the way forward we could solve gerrymandering over night.
The reality is though, that I create these amazing pieces of analysis then have to explain away why that district is odd, y'know, cos the shape is just weird.
Locally they are redoing the district boundaries which is giving me an opportunity to submit my own district shapes that work better with Census data :D
Re: An impossibility theorem for gerrymandering
#8I'm confused about the example. First of all, it seems highly unlikely such a distribution of red and blue votes would occur. But more importantly, blue is a majority of every 3x3 square - why shouldn't it win every district?
Blue is indeed a slight majority of every "3x lattice"-aligned square. But if you take the top left square and shift one down and one right, you'll see that in fact red wins that 3x3 square decisively: 8 to 1.
> why shouldn't it win every district?
Maybe you think it should, but whoever drew the districts would run afoul of the newish gerrymandering measure the Supreme Court is considering.
Re: An impossibility theorem for gerrymandering
#9So the question is if "Minimizing Efficiency Gap" is what we should be aiming for. Its a solid proposal, but I guess its up to the courts to decide if "Efficiency Gap" is a good metric. I guess I'll be interested in hearing the arguments as they come up.
Re: An impossibility theorem for gerrymandering
#10So the question is if "Minimizing Efficiency Gap" is what we should be aiming for. Its a solid proposal, but I guess its up to the courts to decide if "Efficiency Gap" is a good metric. I guess I'll be interested in hearing the arguments as they come up.
I've always thought they should just reverse the order of operations. Instead of having people draw the districts, then machines evaluate them, they should have machines draw a bunch of potential "low efficiency gap" districts, then let people pick the best ones.