I find Cantor's diagonal argument unconvincing. The claim is that there are more real numbers in the range from zero to one than there are natural numbers. To see that this is false simply realize that you don't actually have to write a decimal point to specify the real numbers in this range. Without the decimal point these real numbers just become natural numbers. Can a rational person believe that there are infinit…
Mathematicians Measure Infinities, Find They’re Equal
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Re: Mathematicians Measure Infinities, Find They’re Equal
#32So they basically found a way to represent any real number as an unique sequence of bits? Doesn't sound too hard when spelled like that. I could probably do that, win some prize (not anymore). Do they have anything else like that?
If you've got some free time, can you look into whether or not the real part of every non-trivial zero of the Riemann zeta function is 1/2?
Re: Mathematicians Measure Infinities, Find They’re Equal
#33I find Cantor's diagonal argument unconvincing. The claim is that there are more real numbers in the range from zero to one than there are natural numbers. To see that this is false simply realize that you don't actually have to write a decimal point to specify the real numbers in this range. Without the decimal point these real numbers just become natural numbers. Can a rational person believe that there are infinit…
> To see that this is false simply realize that you don't actually have to write a decimal point to specify the real numbers in this range. Without the decimal point these real numbers just become natural numbers. There are no natural numbers with infinite digits, so this is not correct.
Re: Mathematicians Measure Infinities, Find They’re Equal
#34I find Cantor's diagonal argument unconvincing. The claim is that there are more real numbers in the range from zero to one than there are natural numbers. To see that this is false simply realize that you don't actually have to write a decimal point to specify the real numbers in this range. Without the decimal point these real numbers just become natural numbers. Can a rational person believe that there are infinit…
> Without the decimal point these real
> numbers just become natural numbers.
If your argument is true, presumably you could write a simple program that would generate all the real numbers with a single, infinite loop?I wonder how you'd manage to generate 0.1 and 1.0 with your scheme.
Re: Mathematicians Measure Infinities, Find They’re Equal
#35I find Cantor's diagonal argument unconvincing. The claim is that there are more real numbers in the range from zero to one than there are natural numbers. To see that this is false simply realize that you don't actually have to write a decimal point to specify the real numbers in this range. Without the decimal point these real numbers just become natural numbers. Can a rational person believe that there are infinit…
> Without the decimal point these real numbers just become natural numbers
This is wrong because irrational numbers have an infinite number of digit, if you remove the «dot» you end up with a number infinitely long, which is not a natural number. □
Edit: the set of natural numbers is infinite, which means it can contain arbitrarily big numbers, yet it doesn't contain «numbers» with an infinite amount of digits.
Re: Mathematicians Measure Infinities, Find They’re Equal
#36Edit: real -> rational
Re: Mathematicians Measure Infinities, Find They’re Equal
#37More than one zero, more than one infinity, why not? More than on nothingness, more than one everything..
Re: Mathematicians Measure Infinities, Find They’re Equal
#38Earlier quoted context omitted.
If you've got some free time, can you look into whether or not the real part of every non-trivial zero of the Riemann zeta function is 1/2?
Can you reword this one as a discrete math primer either?
Show that the inequality:
d(n) holds for all n >= 1.
Best I can do, hope that works! [1]
[1] http://www.theoremoftheday.org/NumberTheory/RobinLagarias/To...
Re: Mathematicians Measure Infinities, Find They’re Equal
#39Earlier quoted context omitted.
It is possible. The inverse of m is called q. The function q takes an infinite sequence of coin flips and one by one changes every heads to 1 and every tails to 0. The infinite string of zeros and ones is then prepended with a 1 and interpreted as a transfinite natural number in binary notation. This will not take forever because each change will only take half as long as the previous one. A transfinite natural numbe…
Hundreds of thousands of mathematicians are wrong. No. No natural number has an infinite number of digits, and you are wrong. If you weren't, of course, it would be easy to prove me wrong -- simply name the natural number to which the successor function is applied that results in a "transfinite" number, whatever that is.
But transfinite numbers are not "natural numbers", they are not in the set N, they don't have infinitely many digits, and in the context of this thread, they are a red herring.
Re: Mathematicians Measure Infinities, Find They’re Equal
#40Earlier quoted context omitted.
[I'll try a non technical argument to convince you. It's also not a complete argument, so you must think about this for a while.] > If you believe n is a natural number then you must also believe that n x 10 is a natural number. One more digit! If you interpret the natural number in this way, the important property is that they have only a finite amount of "interesting" digits. Almost all their digits are zero. You c…
>I's much easier to consider the infinite strings of digits like "0.765653625367523765..." or "0.5265362556..." or "0.000073468763478..." and also the one with repetitions like "0.0006767000000..." or "0.0072257822222222...". This is essentially a copy of the real number, but in this copy "0.2999999999999..." is different from "0.300000000000000..." This trick makes much easier to prove that the diagonal ´+1 in each…
Transfinite
This word does not mean what you think it means. I'm not entirely sure what you think it means, but it's definitely not what it means to everyone else.