Earlier quoted context omitted.
Are you one of those people who equates any mention whatsoever of Trump as "being needlessly political"?
Not at all. But bringing him up in an unrelated post on a technical blog just screams "virtue signaling" to me.
A Solution of the P versus NP Problem?
151–160 of 303 posts
Re: A Solution of the P versus NP Problem?
#152I am willing to toss this out of hand...but look at yitang zhang or perelman. who knows? best of luck
Re: A Solution of the P versus NP Problem?
#153Earlier quoted context omitted.
> Nobody's really interested in a proof that P != NP. This is not the case. In my day job I need to worry about what happens if ECDSA is broken. One way that can happen is quantum computation -- but that has a relatively transparent development timeline we can plan for. The other way in which ECDSA could be broken is if P==NP and the discrete log problem can be transformed in polynomial time into another polynomial t…
Knowing P?NP does not imply much in practice unless the answer precisely bounds complexity. N^(N*1e-100) is exponential yet very practical while N^1e100 is polynomial yet is useless in this Universe.
Re: A Solution of the P versus NP Problem?
#154Earlier quoted context omitted.
This interpretation is wrong. The class P contains for example O(N^(10^100000!)), that are not "solvable" by any remotely reasonable meaning of the word.
This is true, but it's difficult to imagine what such a problem could look like. In reality, algorithms tend to come in discrete complexity "units" with very small terms. A linear algorithm isn't just fast -- it tells you something about how such an algorithm works and thus something important about the problem it solves. A quadratic algorithm can be interpreted as a "considers all pairs from the inputs" algorithm. A…
Re: A Solution of the P versus NP Problem?
#155Re: A Solution of the P versus NP Problem?
#156Re: A Solution of the P versus NP Problem?
#157Earlier quoted context omitted.
I think it's even less useful, even if P = NP it is possible that no one finds an algorithm. Creating a (useful) algorithm is independent of proving the theorem. Also interesting is that someone could create an algorithm that solves NP complete in polynomial time without proving P=NP. They would be unable to prove the algorithm correct though.
This is correct. And, in fact, P=NP. However, while P=NP, the algorithm (oracle) resides on the other side of the event horizon. This is called the MAD paradox. https://nerdynotmad.com/p-equals-np/ The submitted proof will be found to be incorrect.
Re: A Solution of the P versus NP Problem?
#158Earlier quoted context omitted.
> serious cahunas I think you mean "cojones" (which btw is a very rude word in Spanish). A kahuna is a kind of Hawai'ian shaman.
I stand corrected, thank you. I would normally have said "serious bollocks", but this forum is mostly left-ponders who would probably not have caught my drift.
Re: A Solution of the P versus NP Problem?
#159I would normally sigh and move on seeing such a claim, but this guy is an established senior researcher at the University of Bonn. A career-ending disaster or instant and eternal fame, that's some serious cahunas.
There's a third possibility: there's a flaw in the proof, but one that is hard to find, and the discovery of the flaw actually advances the field in interesting ways. If I were a betting man that's actually where I'd put my money because the paper passes by bogometer test (but I am nowhere near qualified to assess whether it's actually correct).
Re: A Solution of the P versus NP Problem?
#160I would normally sigh and move on seeing such a claim, but this guy is an established senior researcher at the University of Bonn. A career-ending disaster or instant and eternal fame, that's some serious cahunas.
There's a third possibility: there's a flaw in the proof, but one that is hard to find, and the discovery of the flaw actually advances the field in interesting ways. If I were a betting man that's actually where I'd put my money because the paper passes by bogometer test (but I am nowhere near qualified to assess whether it's actually correct).