Check Widening in LLVM
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Check Widening in LLVM
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Re: Check Widening in LLVM
#2It's good, now. Thanks for taking interest. It's true I was negligent not investigating.
Re: Check Widening in LLVM
#3Re: Check Widening in LLVM
#4Re: Check Widening in LLVM
#5Re: Check Widening in LLVM
#6> Now if arr.length is 1 then we’ll deoptimize to the interpreter with false as the value of 0 u How so? Why does the test change?
In other words, the general optimization is to convert
bool A = condition();
if (!A) { f(A); }
to: bool A = condition();
if (!A) { f(false); }
i.e., that we can assume an if-condition is true within the body of that if-statement. The problem is that the check-widening reuses the body of the if-statement: the code bool A = condition();
if (!A) { f(A); }
bool B = condition();
if (!B) { f(A); }
is converted by check-widening to the first snippet above, which then becomes the second. Sanjoy's observation is that guard-widening is almost correct (we still want to pursue this route) because `f` (the deoptimization escape) is really what we want to call in both cases, but we just need to get the value of `A` right by somehow letting the optimizer know that we're reusing the if-body and that it can't assume anything about the condition that got us there.Also, this is really really clever and I enjoyed the post, OP!
Re: Check Widening in LLVM
#7> Now if arr.length is 1 then we’ll deoptimize to the interpreter with false as the value of 0 u How so? Why does the test change?
The optimizer recognizes that the variable `condition` and the condition with the guard's if-statement are the same (edit: inverses actually), so within the if-statement's body, it can assume that `condition` is false. But when other guard cases are merged in, that's no longer the case. In other words, the general optimization is to convert bool A = condition(); if (!A) { f(A); } to: bool A = condition(); if (!A) { f…
Re: Check Widening in LLVM
#8Why "discard the current runtime frame, and resume execution in the interpreter" rather than jump into a compiled but unoptimized version of the function?
Re: Check Widening in LLVM
#9Fascinating stuff! Reminds me very much of swift's guard statement.
Re: Check Widening in LLVM
#10Earlier quoted context omitted.
The optimizer recognizes that the variable `condition` and the condition with the guard's if-statement are the same (edit: inverses actually), so within the if-statement's body, it can assume that `condition` is false. But when other guard cases are merged in, that's no longer the case. In other words, the general optimization is to convert bool A = condition(); if (!A) { f(A); } to: bool A = condition(); if (!A) { f…
Thanks. I think I understand, but would have liked to see the lowered version with the reused/rewritten condition.