Earlier quoted context omitted.
> millions of Americans use imperial measurements There are two types of countries: those using 'metric' units, and those who have been to the Moon. There's absolutely nothing fundamentally wrong with standard units (indeed, they are better for concrete manipulation). One can do science and engineering just as well with grains as with grams, with cups as with litres, with inches as with centimetres. They could do wit…
I hope you realized NASA using imperial caused the loss of a Mars rover.
Happy Tau Day
91–100 of 128 posts
Re: Happy Tau Day
#92Okay, tau is a little better. Meanwhile, millions of lines of code are written in languages with no type system to speak of, millions of Americans use imperial measurements, billions worldwide speak languages that are inefficient and ambiguous, and many many people aren't even educated enough to know about pi or tau. We have much more damaging problems than multiplying by 2. Given the gigantic amount of effort it wou…
> millions of Americans use imperial measurements There are two types of countries: those using 'metric' units, and those who have been to the Moon. There's absolutely nothing fundamentally wrong with standard units (indeed, they are better for concrete manipulation). One can do science and engineering just as well with grains as with grams, with cups as with litres, with inches as with centimetres. They could do wit…
Also, IMO stuff in decimal is almost always easier to compare than fractional. When someone asks me for a size up from an 8mm wrench, I know to grab the 9mm. When someone asks me for a size up from 5/16", it'll take me a bit to get to 11/32".
Re: Happy Tau Day
#93Earlier quoted context omitted.
"Because that's the way we've always done is" is never a valid argument.
Often it is. It's a perfectly good answer to, for example, "why do we drive on the side of the road that we do?"
It's more or less just a re-statement of the question.
And it's wrong: we haven't always driven on that side of the road.
We don't always drive on that side now; it depends on where in the world we find ourselves.
Left versus right is symmetric: there is no inherent advantage. Both choices have exactly the same advantages and disadvantages, just with "left" and "right" swapped.
Whether or not to include a factor of two isn't symmetric in this way.
Re: Happy Tau Day
#94Earlier quoted context omitted.
If the choice really is arbitrary then yes. If there was a compelling argument to driving one side or the other then it would cease to be a good answer IMHO. https://en.wikipedia.org/wiki/Dagen_H
Given that most people are right handed and right eye dominant it's surprising there isn't a widely accepted 'right answer' for the best side of the road to drive on.
Re: Happy Tau Day
#95Earlier quoted context omitted.
You be the judge of that. Compare e^(iπ) = -1 to e^(iτ) = 1. The whole business of re-writing the identity as e^(iπ) + 1 = 0 is nothing but a hack to get around the weirdness of π as a constant.
Writing it equal to 0 isn't a hack, it's a common method of understanding a function. You factor polynomials by setting them equal to 0, for example. In the case of Euler's identity, what we're really asking is "what values of x make e^(i x ) + 1 = 0 true?" and the answer is "every multiple of π". Using τ instead hides half of the answers.
Re: Happy Tau Day
#96If mathematics has a bikeshed, this is it. I enjoy the ridiculousness of it all, but people who consider this anything other than a well-executed joke really should get a hold of themselves.
Mathematics has no shortage of bikesheds.
Re: Happy Tau Day
#97Earlier quoted context omitted.
You be the judge of that. Compare e^(iπ) = -1 to e^(iτ) = 1. The whole business of re-writing the identity as e^(iπ) + 1 = 0 is nothing but a hack to get around the weirdness of π as a constant.
Writing it equal to 0 isn't a hack, it's a common method of understanding a function. You factor polynomials by setting them equal to 0, for example. In the case of Euler's identity, what we're really asking is "what values of x make e^(i x ) + 1 = 0 true?" and the answer is "every multiple of π". Using τ instead hides half of the answers.
The solutions to
e^(ix) + 1 = 0
are { π, 3π, 5π, ... }
Whereas the solutions to e^(ix) - 1 = 0
are: { 0, 2π, 4π, 3π, ... }
i.e. { 0, τ, 2τ, 3τ, ... }
Also, note that when we set a polynomial to zero, the roots appear subtracted on the opposite side from the independent variable: (x - r0)(x - r1)...(x - rn) = 0
In the Tau-oriented Euler formula written homogeneously, there is a vague analogy to this since we're similarly subtracting that 1: e^(ix) - 1 = 0Re: Happy Tau Day
#98Re: Happy Tau Day
#99What's a nice infinite series summing to tau that isn't merely 2S(n) where S(n) sums to pi?