I wasn't aware you could use const char pointers in switch statements. switch (var) { case "foo": printf("foo block."); break; case "bar": printf("bar block."); break; default: printf("Default case") }
You can't: $ cat foo.c #include main() { const char *foo = "bar"; switch (foo) { case "foo": printf("foo\n"); } } $ gcc -pedantic -std=c99 foo.c -o foo foo.c: In function ‘main’: foo.c:4: error: switch quantity not an integer foo.c:5: error: case label does not reduce to an integer constant
Sorry to make you put in so much work.
I'm aware that you can't do this.
I guess my sarcasm didn't translate:)