I'm probably commenting too late to get my question answered, but here goes: the article has a pretty picture where they show how likely your p-values will mislead you depending on how likely the null hypothesis is. For instance, they say if you think that the null hypothesis has a 50% probability of being right, and you get p=5%, then there's still a 29% chance the null hypothesis is true. But according to my calcul…
Your calculation would be correct only if the assumption "no false negatives" is approximately valid. This is the case when the true value is large in terms of sigma (say mu=6). Then for the 100 cases with mu=0 you'll reject the null 5 times on average, and for each one of the 100 cases with mu=100 you will reject the null (unless you're unlucky: there will be a false negative around once in 150000 trials).
But you're conditioning on pWhen the true value of mu gets closer to 0, you cannot ignore the false negatives. For example if mu=0.1 the rejection rate will be quite similar to the mu=0 case (the probability of getting 0.4Somewhere between the two extreme cases, there is a lower bound for this "false discovery rate".
See http://faculty.washington.edu/jonno/SISG-2011/lectures/sellk... and in particular figure 2.