Build as many words as possible from the given letters
twofx.github.io
Build as many words as possible from the given letters
1–7 of 7 posts
Re: Build as many words as possible from the given letters
#2Which dictionary are you using? Words not in it: DREG, TREND(ED), DEDENT(ED), DENNED...
Re: Build as many words as possible from the given letters
#3Given that you so generously keep the dictionary there, one can just open the console and paste:
words.filter((word) => word.split('').every((letter) => "egtdrnq"].indexOf(letter) !== -1) && word.indexOf('d') !== -1 && word.length>3)
Re: Build as many words as possible from the given letters
#4Which dictionary are you using? Words not in it: DREG, TREND(ED), DEDENT(ED), DENNED...
I did not author the game, and I can't remember the name of the word list, but there is even a video of how the game was built and the word list is part of it: https://www.youtube.com/watch?v=CPhP4NXJFRk
Re: Build as many words as possible from the given letters
#5Q without a U is more or less a dead letter.
Re: Build as many words as possible from the given letters
#6[deleted]
Re: Build as many words as possible from the given letters
#7Given that you so generously keep the dictionary there, one can just open the console and paste: words.filter((word) => word.split('').every((letter) => "egtdrnq"].indexOf(letter) !== -1) && word.indexOf('d') !== -1 && word.length>3) But, of course, that spoils the fun :)
More generally (speed may need to be adjusted):
var letters = $$('.hex').map((x)=>x.textContent.toLowerCase()).join('');
var obLetter = $('.hex.yellow').textContent.toLowerCase();
var sol = words.filter((word) => word.split('').every((letter) => letters.indexOf(letter) !== -1) && word.indexOf(obLetter) !== -1 && word.length>3);
let tick = 0;
let nextWord = ()=>{
$('#textInput').value=sol[tick].toUpperCase();
$('.enter-button').click();
tick++;
if(tick