I can code that FizzBuzz function with only two tests

#1

Post by plastic_teeth » Tue, Jun 09, 2020, 6:43 AM UTC

Re: I can code that FizzBuzz function with only two tests

#2

Post by rethab » Tue, Jun 09, 2020, 7:50 AM UTC

Or with AWK: echo 15 | awk '$1%3==0{s=s"Fizz"} $1%5==0{s=s"Buzz"} END{print s}'

#3

Post by eesmith » Tue, Jun 09, 2020, 9:16 AM UTC

rethab wrote: post #2

Or with AWK: echo 15 | awk '$1%3==0{s=s"Fizz"} $1%5==0{s=s"Buzz"} END{print s}'

Not that it affects your overall point, but you probably want:

  awk '$1%3==0{s=s"Fizz"} $1%5==0{s=s"Buzz"} {print s;s=""}'

Otherwise, consider:

  % printf "3\n5\n9\n15\n16\n" | awk '$1%3==0{s=s"Fizz"} $1%5==0{s=s"Buzz"} END{print s}'
  FizzBuzzFizzFizzBuzz

For bonus points, the following won't treat non-numerics as FizzBuzz:

  awk '$1+0\!=$1 {print"";next} $1%3==0{s=s"Fizz"} $1%5==0{s=s"Buzz"} {print s;s=""}'

#4

Post by brudgers » Tue, Jun 09, 2020, 1:20 PM UTC

There is no clever way to compute FizzBuzz. It is a constant.