The Riemann Hypothesis, explained (2016)
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The Riemann Hypothesis, explained (2016)
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Re: The Riemann Hypothesis, explained (2016)
#2Re: The Riemann Hypothesis, explained (2016)
#3> The fourth and final term is an integral which is zero for x This does not seem correct. Overall a good article though.
Re: The Riemann Hypothesis, explained (2016)
#4Re: The Riemann Hypothesis, explained (2016)
#5Re: The Riemann Hypothesis, explained (2016)
#6Prime Obsession, by John Derbyshire, is a very entertaining and well written book about this topic, following a similar path (although much slower) among the conceptual building blocks required to understand the hypothesis.
https://www.google.com/amp/s/amp.theguardian.com/world/2012/...
Re: The Riemann Hypothesis, explained (2016)
#7Prime Obsession, by John Derbyshire, is a very entertaining and well written book about this topic, following a similar path (although much slower) among the conceptual building blocks required to understand the hypothesis.
John Derbyshire has become a controversial figure: https://www.google.com/amp/s/amp.theguardian.com/world/2012/...
Re: The Riemann Hypothesis, explained (2016)
#8Prime Obsession, by John Derbyshire, is a very entertaining and well written book about this topic, following a similar path (although much slower) among the conceptual building blocks required to understand the hypothesis.
John Derbyshire has become a controversial figure: https://www.google.com/amp/s/amp.theguardian.com/world/2012/...
Re: The Riemann Hypothesis, explained (2016)
#9> The fourth and final term is an integral which is zero for x This does not seem correct. Overall a good article though.
Re: The Riemann Hypothesis, explained (2016)
#10> The fourth and final term is an integral which is zero for x This does not seem correct. Overall a good article though.
I was doing some reading about the Rieman hypotesis like a month ago - when searching I came across this very same post - not sure if here or somewhere else, but I read that the stric definition of a prime number (It has to be divisible only by itself, and obviously _also_ by 1) rules out 1 bcause it is only divisible by itself. I mean, it is divisible by one, but that doesn't count as _also_.
https://en.wikipedia.org/wiki/Fundamental_theorem_of_arithme...