WanaCrypt0r Ransomworm
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WanaCrypt0r Ransomworm
1–10 of 71 posts
Re: WanaCrypt0r Ransomworm
#2Would it be easy to find it if the initial attack vector uses some semi-obscure torrent? Would people find out quickly?
Re: WanaCrypt0r Ransomworm
#315.13562354 BTC = $26410 13.78022431 BTC = $24045 5.98851225 BTC = $17361
Assuming $300 per ransom, this works out to a total of 226 victims who paid. this seems a little low compared to the huge amount of infected devices.
Re: WanaCrypt0r Ransomworm
#4I think this is an important take-away. I found it strange that so many media outlets and IT departments were jumping on the "do not open suspicious emails" bandwagon even although there hasn't been a lot of evidence of such phishing emails. That is: screenshots of infected devices have been popping up all across the world, but almost no examples of a particular entry email have been shown.
Of course, it might be easier for an IT dep. to state: "it must have been unleashed by someone clicking on some email they got" rather than "oops, we still had unpatched Windows machines exposed to the public internet". Why go through the trouble of sending out emails when your worm already contains a replication/infection mechanism. Just use a botnet to scan those 1 million IPs and see if SMB is open.
That being said, it does not surprise me to see yet again an issue in SMB. This has been a particularly weak point in Windows for decades now. I remember "hacking tutorials" from 15 years ago where you'd just go out and nmap public IP ranges to see if you could access hidden shares (e.g. like so: http://www.madirish.net/59). Also there was this issue of Windows keeping weak NetBIOS password hashes around which could be trivially unhashed (https://vuldb.com/?id.13824), years ago.
Re: WanaCrypt0r Ransomworm
#5according to the article, the balances of the bitcoin addresses collecting the ransoms are 15.13562354 BTC = $26410 13.78022431 BTC = $24045 5.98851225 BTC = $17361 Assuming $300 per ransom, this works out to a total of 226 victims who paid. this seems a little low compared to the huge amount of infected devices.
They could have already moved a part of the coins to an exchange.
Re: WanaCrypt0r Ransomworm
#6according to the article, the balances of the bitcoin addresses collecting the ransoms are 15.13562354 BTC = $26410 13.78022431 BTC = $24045 5.98851225 BTC = $17361 Assuming $300 per ransom, this works out to a total of 226 victims who paid. this seems a little low compared to the huge amount of infected devices.
Re: WanaCrypt0r Ransomworm
#7according to the article, the balances of the bitcoin addresses collecting the ransoms are 15.13562354 BTC = $26410 13.78022431 BTC = $24045 5.98851225 BTC = $17361 Assuming $300 per ransom, this works out to a total of 226 victims who paid. this seems a little low compared to the huge amount of infected devices.
https://www.trustar.co/wp-content/uploads/2017/05/WannaCryVe...
Re: WanaCrypt0r Ransomworm
#8"As noted in our attribution post last year, use of Visual Studio 6.0 is not a significant observation on its own – however, this development environment dates from 1998 and is rarely used by malware coders. Nonetheless, it has been seen repeatedly with Lazarus attacks."
Re: WanaCrypt0r Ransomworm
#9according to the article, the balances of the bitcoin addresses collecting the ransoms are 15.13562354 BTC = $26410 13.78022431 BTC = $24045 5.98851225 BTC = $17361 Assuming $300 per ransom, this works out to a total of 226 victims who paid. this seems a little low compared to the huge amount of infected devices.
Re: WanaCrypt0r Ransomworm
#10according to the article, the balances of the bitcoin addresses collecting the ransoms are 15.13562354 BTC = $26410 13.78022431 BTC = $24045 5.98851225 BTC = $17361 Assuming $300 per ransom, this works out to a total of 226 victims who paid. this seems a little low compared to the huge amount of infected devices.
Did you check the transactions? They could have already moved a part of the coins to an exchange.