Stuff you might didn't know about CoffeeScript

Post by martin-adams » Mon, Jan 04, 2016, 12:35 PM UTC

  a = 10  
  b = 5 > a > 30

  var a, b;

  a = 10;  
  b = (5 > a && a > 30); 

  b = 5  30

Post by martin-adams » Mon, Jan 04, 2016, 9:02 PM UTC

rec wrote: post #3

martin-adams wrote: post #2

I found the following example to be extremely confusing: a = 10 b = 5 > a > 30 When I thought about it after seeing what it compiles to: var a, b; a = 10; b = (5 > a && a > 30); I couldn't see how that statement could be true because a cannot be less than 5 while also be greater than 30. Range checking I would assume would be: b = 5 30

You are absolutely right! The range check would be "`5` is less than `a` and `a` is less than `30`". Meaning that `a` is between 5 and 30. It's fixed now. Thanks martin-adams!