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Bard Extensions

bard.google.com

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Re: Bard Extensions

#91
post #74

Can someone in the know explain how Bard could be as bad as it is, considering Google has been investing in AI for as long as they have? I thought they were earlier than most to begin serious work on AI? How could Bard suck this bad?

The answer is some combination of two phenomena: 1. The Innovator's Dilemma ( https://en.wikipedia.org/wiki/The_Innovator%27s_Dilemma ) This is the premise that a mature incumbent will usually fail to respond fast enough to disruptive innovations by an upstart because their organization is optimized to continue providing existing customers sustaining improvements to the products they are already paying for. 2. The Co…

This is exactly the kind of reply I was hoping to get, thanks for the info!

Re: Bard Extensions

#92
post #88
post #79

Earlier quoted context omitted.

Yes, I'm using 3.5, but that's the free version, and I don't need AI often enough to want to pay $20 for version 4.

3.5 is a weak model that is only good at informal conversation. When people talk about using ChatGPT and its potential (programming, vision, etc.) they talk about GPT-4. If you don't want to pay, you should use Bing Chat for your comparison. 3.5 would not be worth $20 a month but GPT-4 is.

It's funny to me how often this mistake is being made here on HN, despite this exact thing being repeated time and again. There is a big difference between 3.5 and 4.

Re: Bard Extensions

#93

Can someone in the know explain how Bard could be as bad as it is, considering Google has been investing in AI for as long as they have? I thought they were earlier than most to begin serious work on AI? How could Bard suck this bad?

[deleted]

Re: Bard Extensions

#94
post #62

Can someone in the know explain how Bard could be as bad as it is, considering Google has been investing in AI for as long as they have? I thought they were earlier than most to begin serious work on AI? How could Bard suck this bad?

I put all questions to both Bard and chatGPT. The exact same words. Bard is almost always better. For example try: "why does my hole saw have a spring over the drill bit?" Bard is correct, chatGPT makes up nonsense. (There's no such thing as "pilot bit extension spring", and the rest of the reply makes little sense as well.) https://chat.openai.com/share/485a6968-6379-4f64-87b3-6c1575... https://g.co/bard/share/01c5b…

You asked on ChatGPT 3.5. Yes, Bard (PaLM) is better. Now compare with GPT4 ;)

Re: Bard Extensions

#95
post #62

Earlier quoted context omitted.

I put all questions to both Bard and chatGPT. The exact same words. Bard is almost always better. For example try: "why does my hole saw have a spring over the drill bit?" Bard is correct, chatGPT makes up nonsense. (There's no such thing as "pilot bit extension spring", and the rest of the reply makes little sense as well.) https://chat.openai.com/share/485a6968-6379-4f64-87b3-6c1575... https://g.co/bard/share/01c5b…

I've been asking science and math questions to Bard and ChatGPT (at about an undergraduate level) and likewise found Bard to be consistently better. As an example I asked both how many groups there are of order 6. Bard gave the correct answer of 2 and listed what they were. ChatGPT said there were five and proceeded to list seven.

GPT-4 gets the answer of 2 on the first try (https://chat.openai.com/share/0cf623c1-453f-4abc-a6f9-74f1af...):

> Q:

> How many groups are there of order 6?

> A:

> There are two groups of order 6.

> To determine this, we consider the possible structures of a group of order 6. Since 6 = 2 × 3, where both 2 and 3 are prime numbers, the groups of order 6 can either be cyclic or a direct product of smaller cyclic groups.

> Cyclic Group of Order 6: There is always one cyclic group for any given order. The cyclic group of order 6 is denoted as 𝐶₆ or ℤ₆, which is generated by an element of order 6.

> Non-Cyclic Group: The other possibility is a non-cyclic group. By Sylow's theorems, the number of elements of order 2 must divide 3 and be congruent to 1 modulo 2, and the number of elements of order 3 must divide 2 and be congruent to 1 modulo 3. This means there must be one Sylow 2-subgroup and one Sylow 3-subgroup. The non-cyclic group of order 6 is the symmetric group 𝑆₃, which is the group of all permutations of three objects. It is non-abelian and can also be thought of as the semi-direct product of 𝐶₂ and 𝐶₃.

> So, there are two groups of order 6: the cyclic group ℤ₆ and the symmetric group 𝑆₃.

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