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Draw an iceberg and see how it will float

joshdata.me

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Re: Draw an iceberg and see how it will float

#61
post #16

Got a bit frustrated because I couldn't get anything except a flat surface above the water, then read the tweets below and realised that's the entire point: https://threadreaderapp.com/thread/1362557149147058178.html (Many thanks to Elon for making it impossible to read more than the first tweet on x.com without an account...)

> (Many thanks to Elon for making it impossible to read more than the first tweet on x.com without an account...)

https://threadreaderapp.com/thread/1362557149147058178.html

Re: Draw an iceberg and see how it will float

#62
post #50

Earlier quoted context omitted.

There isn't necessarily just one. A rectangle-ish form could have 4.

Yes, rectangle would also be degenerate. Basically any configuration where adding an epsilon weight somewhere generates a non-epsilon shift so to speak.

To me, "degenerate" means that it has a symmetry so that the different states are somehow identical (e.g. equal energy in a quantum system). If it's rectangle-ish (say, an imperfect hand-drawn rectangle) then it has 4 distinct equilibrium positions. Not sure if we're thinking of the same with "degenerate".
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