Earlier quoted context omitted.
Imagine you just land a tiny craft on that thing and let the thing take you to interestelar space without you having to burn no more fuel. Unfortunately, if you can't catch it, you don't need it for that, as you'll be traveling faster that it to be able to intercept it and would just burn fuel trying to break enough to match its speed.
Rule 1 of orbital mechanics: if you're about to dock with something, you're already on the same trajectory as that thing. Might make a good radiation shield, though.
Oumuamua may be a hydrogen iceberg
61–70 of 96 posts
Re: Oumuamua may be a hydrogen iceberg
#62Earlier quoted context omitted.
I'm not sure of what definition they used here, but one that is common is heliosphere, or in other words sphere around the Sun where solar wind is dominant. This is about 120 AU.
‘Oumuamua's incoming and outgoing speed is ~5AU/year. In 10,000 years that's 50,000AU, which is approximately the distance to the outer most region of the Oort Cloud: https://en.wikipedia.org/wiki/Oort_cloud
Re: Oumuamua may be a hydrogen iceberg
#63Makes me wonder if you could slingshot around the sun towards relativistic speeds with thermal power. At the very least it could save fuel on the egress, if not the second half. Can you aerobrake around a star?
Re: Oumuamua may be a hydrogen iceberg
#64Earlier quoted context omitted.
Rule 1 of orbital mechanics: if you're about to dock with something, you're already on the same trajectory as that thing. Might make a good radiation shield, though.
I'm not into orbital mechanics at all, just an interested layman, but how does a space tug work in relation to your 'Rule 1 of orbital mechanics'?. What is the point of a space tug then?
It boils down to the fact that in space you can, with a very good degree of approximation, determine the trajectory of an object not under thrust, knowing only these two things: it's position at a given time, and it's velocity at that same time. These two vectors give you a single trajectory through space.
It follows from two physical laws that you may remember from high school:
- Newton's second law, or F=ma
- Newton's law of universal gravitation, or F=GMm/r^2
If you put them against each other, you get ma=GMm/r^2, or consequently a=GM/r^2. The acceleration (and thus, future position and velocity) of an inert object in space is independent of its mass. So all you need to tell where it will go is to know where it is, and what is it's current speed and direction of movement. And, of course, what other bodies influence it with their gravity.
Of course, in practice, there are other considerations in which the mass may become relevant. For instance, solar radiation acts on the surface, impacting force that's scaled by object's mass. The same is true for collisions with various stray atoms, especially prevalent near planets with atmospheres.
But discounting above factors (and, again, you can go pretty far just ignoring them), if you have two objects very close to each other and not moving relative to each other, they'll just go together along the same path for a long, long time.
Re: Oumuamua may be a hydrogen iceberg
#65Makes me wonder if you could slingshot around the sun towards relativistic speeds with thermal power. At the very least it could save fuel on the egress, if not the second half. Can you aerobrake around a star?
If you can keep your cool, why not? Matter is matter.
What's better, you could technically radiation-brake around a star. I don't know how big of a solar sail you'd have to present to get a meaningful force from it.
Re: Oumuamua may be a hydrogen iceberg
#66Earlier quoted context omitted.
Rule 1 of orbital mechanics: if you're about to dock with something, you're already on the same trajectory as that thing. Might make a good radiation shield, though.
Except this is not an orbit around any body. If you can do what the parent proposes, you can add the chemical energy of fusing the hydrogen to your kinetic energy and defeat the rocket equation
Re: Oumuamua may be a hydrogen iceberg
#67Earlier quoted context omitted.
I'm not into orbital mechanics at all, just an interested layman, but how does a space tug work in relation to your 'Rule 1 of orbital mechanics'?. What is the point of a space tug then?
One of the purposes of a proposed 'space tug' is to use slow low thrust but high delta-v, high efficiency engines to do things such as: Raise the orbit of satellites in LEO which are affected by atmospheric drag. Or re-boost things like the international space station, proposed future Chinese space station, etc. Extend the lifetime of geostationary satellites which are still electrically functional, but out of statio…
Re: Oumuamua may be a hydrogen iceberg
#68Earlier quoted context omitted.
‘Oumuamua's incoming and outgoing speed is ~5AU/year. In 10,000 years that's 50,000AU, which is approximately the distance to the outer most region of the Oort Cloud: https://en.wikipedia.org/wiki/Oort_cloud
I always thought the Oort cloud was a scientifically proven thing but apparently it's "a theoretical cloud of predominantly icy planetesimals proposed to surround the Sun at distances ranging from 2,000 to 200,000 au (0.03 to 3.2 light-years)"
Re: Oumuamua may be a hydrogen iceberg
#69Earlier quoted context omitted.
‘Oumuamua's incoming and outgoing speed is ~5AU/year. In 10,000 years that's 50,000AU, which is approximately the distance to the outer most region of the Oort Cloud: https://en.wikipedia.org/wiki/Oort_cloud
I always thought the Oort cloud was a scientifically proven thing but apparently it's "a theoretical cloud of predominantly icy planetesimals proposed to surround the Sun at distances ranging from 2,000 to 200,000 au (0.03 to 3.2 light-years)"
It’s curious to note that the proposed outer limit of the Oort cloud (3.2 ly) is more than half the distance to the closest star system (4.4 ly) [1] though I’m unclear whether the cloud would be roughly spherical or have some sort of directionality.
Re: Oumuamua may be a hydrogen iceberg
#70Earlier quoted context omitted.
Hey let's probe the boundary conditions of the universe.
The boundary condition is that at some arbitrary point god smacks you and tells you to knock it off