For context, 120 PeV is about 10% the kinetic energy of a ping pong ball during typical play.
Now, what will happen if you get hit by a ping-pong ball mass of 120 PeV neutrinos? 120 PeV is about 2e-16 grams, so a ping-pong ball will have about 1e16 of them. From nothing, to detectable, to lethal, to big boom? My intuition would be "detectable" but I don't know enough to do the maths. And by the way, I am using the mass-energy, not proper mass, because the question is crazy enough not to even consider what wou…
The probability of interaction of neutrinos with matter increases with the energy. I've asked o1 to estimate the mean free path of a 120 PeV neutrino in water and it came up with 1000km. So let's say, conservatively, that 10^-7 of the total energy gets deposited in your body when the beam goes through. The mass equivalent of a ping pong ball is about 2.5x10^14 J, which gives us 2.5x10^7 J total, or about 6kg TNT equivalent. This is only an order-of-magnitude estimate, but it would definitely not be healthy.