I like it, but the array details are a little bit off. An actual array does have a known size, that's why when given a real array `sizeof` can give the size of the array itself rather than the size of a pointer. There's no particular reason why C doesn't allow you to assign one array to another of the same length, it's largely just an arbitrary restriction. As you noted, it already has to be able to do this when assi…
int arr[5][7];
arr[3][5] = 4; // equivalent to *(*(arr + 3) + 5) = 4;
This works because (arr + 3) has type "pointer to int[7]", not "pointer to int". The resulting address computation is (char*)arr + 3 * sizeof(int[7]) + 5 * sizeof(int) ==
(char*)arr + 26 * sizeof(int)
That's also another reason why types like "int [5][7][]" are legal but "int [5][][]" are not.