I know of at least one, and it's annoying when Facebook does that 'hey, you haven't talked to this person in a while, write them a message' thing. There needs to be a way for the deceased to have accounts either deactivated or taken out of regular circulation.
The rise of the dead: How many ghosts are on Facebook?
31–37 of 37 posts
Re: The rise of the dead: How many ghosts are on Facebook?
#32Earlier quoted context omitted.
Well, populations are typically modeled as a sigmoid function, they only appear to be growing exponentially. I think it's fair to assume total population will stabilise whilst we are still resource limited to Earth.
It seems that we are at the inflection point of the sigmoid: http://upload.wikimedia.org/wikipedia/commons/7/77/World-Pop...
Re: The rise of the dead: How many ghosts are on Facebook?
#33Reminded me of this XKCD http://xkcd.com/686/ Which just made me sad.
Re: The rise of the dead: How many ghosts are on Facebook?
#34Reminded me of this XKCD http://xkcd.com/686/ Which just made me sad.
A certain IRC network has also, apparently, made an exception to its policy on expiring registered nicks -- nine months later, his is still registered and protected. Which is a nice gesture.
Re: The rise of the dead: How many ghosts are on Facebook?
#35Do they really have to be called 'ghosts'?
Re: The rise of the dead: How many ghosts are on Facebook?
#36The guys at www.entrustet.com have been talking about this for the last 6 months. Some of 1000 memories points are straight up lifted. Have some integrity guys. The interwebs know when you copy. Stats are free, but you should at least credit them for inspiration.
Re: The rise of the dead: How many ghosts are on Facebook?
#37The guys at www.entrustet.com have been talking about this for the last 6 months. Some of 1000 memories points are straight up lifted. Have some integrity guys. The interwebs know when you copy. Stats are free, but you should at least credit them for inspiration.
Isn't the moral of Hacker News that the ideas don't matter that much, only the execution?